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Thistle Hunt
        LeWiz24 edited this page Aug 27, 2024 
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    TIP102 Unit 1 Session 1 Standard (Click for link to problem statements)
- 💡 Difficulty: Easy
- ⏰ Time to complete: 5 mins
- 🛠️ Topics: Lists, Loops
Understand what the interviewer is asking for by using test cases and questions about the problem.
- 
Q: What should the function return if the list itemsdoes not contain any"thistle"?- A: The function should return an empty list [].
 
- A: The function should return an empty list 
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Q: Should the function be case-sensitive when searching for "thistle"?- A: Yes, the function should be case-sensitive and only return indices of elements that exactly match "thistle".
 
- A: Yes, the function should be case-sensitive and only return indices of elements that exactly match 
- 
The function locate_thistles()should take a list of strings items and return a list of the indices where the value is "thistle".
HAPPY CASE
Input: ["thistle", "stick", "carrot", "thistle", "eeyore's tail"]
Expected Output: [0, 3]
EDGE CASE
Input: ["book", "bouncy ball", "leaf", "red balloon"]
Expected Output: []
Plan the solution with appropriate visualizations and pseudocode.
General Idea: Define a function that iterates through the list and records the indices where the value is "thistle".
1. Define the function `locate_thistles(items)`.
2. Initialize an empty list `indices` to store the indices.
3. Iterate through the list using a range to get both index and item.
4. For each item, check if it is equal to `"thistle"`.
5. If it is, add the index to `indices`.
6. Return the `indices` list.- Not correctly iterating through all elements of the input list.
- Misplacing or misidentifying the indices.
Implement the code to solve the algorithm.
def locate_thistles(items):
    # Initialize an empty list to store the indices
    indices = []
    
    # Iterate through the list using range to get both index and item
    for i in range(len(items)):
        # If the item is "thistle", add its index to the list
        if items[i] == "thistle":
            indices.append(i)
    
    # Return the list of indices
    return indices