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R Stats: Addition Rule and Monty Hall Problem
Abish Pius edited this page Feb 21, 2020
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- The addition rule states that the probability of event A or event B happening is the probability of event A plus the probability of event B minus the probability of both events A and B happening together.
Pr(A or B)=Pr(A)+Pr(B)−Pr(A and B) - Note that (A or B) is equivalent to (A|B)
- We apply the addition rule where A = drawing an ace then a facecard and B = drawing a facecard then an ace. Note that in this case, both events A and B cannot happen at the same time, so Pr(A and B) = 0.
Pr(ace then facecard) = 4/52 x 16/51
Pr(facecard then ace) = 16/52 x 4/51
Pr(ace then facecard | facecard then ace) = 4/52 x 16/51 + 16/52 x 4/51
- Monte Carlo simulations can be used to simulate random outcomes, which makes them useful when exploring ambiguous or less intuitive problems like the Monty Hall problem.
- In the Monty Hall problem, contestants choose one of three doors that may contain a prize. Then, one of the doors that was not chosen by the contestant and does not contain a prize is revealed. The contestant can then choose whether to stick with the original choice or switch to the remaining unopened door.
- Although it may seem intuitively like the contestant has a 1 in 2 chance of winning regardless of whether they stick or switch, Monte Carlo simulations demonstrate that the actual probability of winning is 1 in 3 with the stick strategy and 2 in 3 with the switch strategy.
- For more in-depth details click here
B <- 10000
stick <- replicate(B, {
doors <- as.character(1:3)
prize <- sample(c("car","goat","goat")) # puts prizes in random order
prize_door <- doors[prize == "car"] # note which door has prize
my_pick <- sample(doors, 1) # note which door is chosen
show <- sample(doors[!doors %in% c(my_pick, prize_door)],1) # open door with no prize that isn't chosen
stick <- my_pick # stick with original door
stick == prize_door # test whether the original door has the prize
})
mean(stick) # probability of choosing prize door when stickingswitch <- replicate(B, {
doors <- as.character(1:3)
prize <- sample(c("car","goat","goat")) # puts prizes in random order
prize_door <- doors[prize == "car"] # note which door has prize
my_pick <- sample(doors, 1) # note which door is chosen first
show <- sample(doors[!doors %in% c(my_pick, prize_door)], 1) # open door with no prize that isn't chosen
switch <- doors[!doors%in%c(my_pick, show)] # switch to the door that wasn't chosen first or opened
switch == prize_door # test whether the switched door has the prize
})
mean(switch) # probability of choosing prize door when switching