Adding all the solutions

[subbu4061]

No description provided.

[super30admin]

Strengths:

• The solution correctly implements the prime multiplication approach to group anagrams.
• The code is well-commented and easy to understand.
• Edge cases are handled appropriately.

Areas for Improvement:

• The edge cases (empty input and single element) are redundant because the main logic already handles them. You can remove these checks to simplify the code.
• Consider using a double for the hash product instead of BigInteger for better performance, as the maximum string length is 100. The product of 100 primes (each up to 101) will be within the range of a double without losing precision for grouping purposes. However, if you are concerned about precision, BigInteger is safe but slower.
• Instead of checking if the key exists and then getting the list, you can use map.computeIfAbsent(key, k -> new ArrayList<>()).add(curr) to make the code more concise.

Example of improved code:

import java.util.*;

class Solution {
    public List<List<String>> groupAnagrams(String[] strs) {
        Map<Double, List<String>> map = new HashMap<>();
        int[] primes = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101};
        for (String curr : strs) {
            double product = 1.0;
            for (char c : curr.toCharArray()) {
                product *= primes[c - 'a'];
            }
            map.computeIfAbsent(product, k -> new ArrayList<>()).add(curr);
        }
        return new ArrayList<>(map.values());
    }
}

Note: The above code uses double, which is efficient and sufficient for the given constraints.