Assignment one

02_activities/assignments/Cohort_8/assignment1.sql

@@ -4,20 +4,23 @@
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
+
 SELECT *
 FROM customer;
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
+
 SELECT *
 FROM customer
 ORDER By customer_last_name, customer_first_name
 LIMIT 10;
 
 
 --WHERE
-/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
+/* 1.Write a query that returns all customer purchases of product IDs 4 and 9. */
+
 SELECT *
 FROM customer_purchases
 WHERE customer_id IN (4, 9);
@@ -32,18 +35,19 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
 
 
 -- option 2
+
 SELECT *,
 (quantity*cost_to_customer_per_qty) AS price
 From customer_purchases
 WHERE customer_id BETWEEN 8 AND 10;
 
 
-
 --CASE
 /* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. 
 Using the product table, write a query that outputs the product_id and product_name
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
+
 SELECT product_id, product_name,
 CASE 
 WHEN product_qty_type = 'unit' THEN 'unit'
@@ -56,6 +60,7 @@ FROM product;
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
+
 SELECT product_id, product_name
 ,CASE 
 WHEN product_qty_type = 'unit' THEN 'unit'
@@ -71,6 +76,7 @@ FROM product;
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
+
 SELECT
 vendor.vendor_id,
 vendor.vendor_name,
@@ -88,6 +94,7 @@ ORDER by vendor.vendor_name, vb.market_date;
 -- AGGREGATE
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
+
 SELECT vendor_id,
 count (*) as vendor_booth_counts
 FROM vendor_booth_assignments
@@ -99,6 +106,7 @@ of customers for them to give stickers to, sorted by last name, then first name.
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
+
 SELECT customer.customer_id,
 customer.customer_first_name,
 customer.customer_last_name,
@@ -125,6 +133,7 @@ When inserting the new vendor, you need to appropriately align the columns to be
 -> To insert the new row use VALUES, specifying the value you want for each column:
 VALUES(col1,col2,col3,col4,col5) 
 */
+
 CREATE TABLE temp.new_vendor_copy2 as 
 SELECT * 
 From vendor;
@@ -141,6 +150,7 @@ VALUES (10, 'Thomass Superfood Store', 'Fresh Focused store', 'Thomas', 'Rosenth
 HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
 and year are! */
 
+
 SELECT 
     customer_id,
     strftime('%m', market_date) AS month,
@@ -155,6 +165,7 @@ Remember that money spent is quantity*cost_to_customer_per_qty.
 HINTS: you will need to AGGREGATE, GROUP BY, and filter...
 but remember, STRFTIME returns a STRING for your WHERE statement!! */
 
+
 SELECT customer_id,
 sum (quantity * cost_to_customer_per_qty) as total_spent_apr_2022
 from customer_purchases