adding assignment 5 - Riva

Assignment 1_Deadline 26 Sept 2017/assignment1_step1_Genco.py

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+#determination of the total thermal resistance and the heat transfer rate throw a Composite Wall
+
+H = 3 #height of the wall
+W = 5 #width of the wall
+ht = 0.25 #total height of the unit
+hb = 0.22 #height of the brick
+hp = 0.015 #height of the plaster
+wf = 0.03 #width of the foam
+wp = 0.02 #width of the plaster layers
+wb = 0.16 #width of the brick
+k1 = 0.026 #foam conduction heat transfer
+k2 = 0.22 #plaster conduction heat transfer
+k3 = 0.72 #brick conduction heat transfer
+h1 = 10 #inside convenction heat trasfer
+h2 = 25 #outside convenction heat trasfer
+t1 = 20 #temperature inside
+t2 = -10 #temperature outside
+
+#Resistence 
+Rconv = 1/(h1*ht*1)
+R1 = wf/(k1*ht*1) #foam Resistence
+R2 = R6 = wp/(k2*ht*1) # the two plaster side resistence
+R3 = R5 = wb/(k2*hp*1) # Plaster center Resistence
+R4 = wb/(k3*hb*1) # Brick Resistence
+R0 = 1/(h2*ht*1)  #second convention resistence
+
+Rp = ( (1/R3) + (1/R4) + (1/R5) )
+RP = 1/Rp #sum of the three resistence in the middle, they are in parallel
+
+Rt = Rconv+R1+R2+RP+R6+R0
+
+Q = (t1-(t2))/Rt #heat transfer through the wall
+s = (ht*1) #surface area in m^2
+Q1 = Q/s #heat transfer per m^2 area
+A = H * W #total area
+
+Qt = Q1*A
+
+
+print"The amount of heat transfer of the entire wall is "+str (Qt)+" degC/W"
+print"The amount of thermal resistence of the brick is "+str (Rt)+" W"

Assignment 1_Deadline 26 Sept 2017/assignment1_step1_riva.py

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+#ASSIGNMENT 1
+
+H = 3 #height of the wall
+W = 5 #width of the wall
+ht = 0.25 #total height of the unit
+hb = 0.22 #height of the brick
+hp = 0.015 #height of the plaster
+wf = 0.03 #width of the foam
+wp = 0.02 #width of the plaster layers
+wb = 0.16 #width of the brick
+k1 = 0.026 #foam conduction heat transfer
+k2 = 0.22 #plaster conduction heat transfer
+k3 = 0.72 #brick conduction heat transfer
+h1 = 10 #inside convenction heat trasfer
+h2 = 25 #outside convenction heat trasfer
+t1 = 20 #temperature inside
+t2 = -10 #temperature outside
+
+#Res
+Rconv = 1/(h1*ht*1)
+R1 = wf/(k1*ht*1) #foam Res
+R2 = R6 = wp/(k2*ht*1) # the two plaster side res
+R3 = R5 = wb/(k2*hp*1) # Plaster center Res
+R4 = wb/(k3*hb*1) # Brick Res
+R0 = 1/(h2*ht*1)  #second convention res
+
+Rp = ( (1/R3) + (1/R4) + (1/R5) )
+RP = 1/Rp #sum of the three res in the middle, they are in parallel
+
+Rt = Rconv+R1+R2+RP+R6+R0
+
+Q = (t1-(t2))/Rt #heat transfer through the wall
+s = (ht*1) #surface area in m^2
+Q1 = Q/s #heat transfer per m^2 area
+A = H * W #total area
+
+Qt = Q1*A
+
+
+print"The amount of heat transfer of the entire wall is "+str (Qt)+" degC/W"
+print"The amount of thermal resistence of the brick is "+str (Rt)+" W"

Assignment 1_Deadline 26 Sept 2017/assignment1_step2_Genco.py

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+H = 3 #height of the wall
+W = 5 #width of the wall
+ht = 0.25 #total height of the unit
+hb = 0.22 #height of the brick
+hp = 0.015 #height of the plaster
+wf = 0.03 #width of the foam
+wp = 0.02 #width of the plaster layers
+wb = 0.16 #width of the brick
+k1 = float (raw_input("enter the thermal conductivity of the foam in W/(degC*m) "))#foam conduction heat transfer
+k2 = float (raw_input("enter the thermal conductivity of the plaster in W/(degC*m) ")) #plaster conduction heat transfer
+k3 = float (raw_input("enter the thermal conductivity of the brick in W/(degC*m) ")) #brick conduction heat transfer
+h1 = float (raw_input("enter the internal convenction heat transfer W/(degC*m^2) "))#inside convenction heat trasfer
+h2 = float (raw_input("enter the external convenction heat tranfer W/(degC*m^2) "))#outside convenction heat trasfer
+t1 = float (raw_input("enter the internal temperature in degC ")) #temperature inside
+t2 = float (raw_input("enter the external temperature in degC ")) #temperature outside
+
+#Resistence 
+Rconv = 1/(h1*ht*1)
+R1 = wf/(k1*ht*1) #foam Resistence
+R2 = R6 = wp/(k2*ht*1) # the two plaster side resistence
+R3 = R5 = wb/(k2*hp*1) # Plaster center Resistence
+R4 = wb/(k3*hb*1) # Brick Resistence
+R0 = 1/(h2*ht*1)  #second convention resistence
+
+Rp = ( (1/R3) + (1/R4) + (1/R5) )
+RP = 1/Rp #sum of the three resistence in the middle, they are in parallel
+
+Rt = Rconv+R1+R2+RP+R6+R0
+
+Q = (t1-(t2))/Rt #heat transfer through the wall
+s = (ht*1) #surface area in m^2
+Q1 = Q/s #heat transfer per m^2 area
+A = H * W #total area
+
+Qt = Q1*A
+
+
+print"The amount of heat transfer of the entire wall is "+str (Qt)+" degC/W"
+print"The amount of thermal resistence of the brick is "+str (Rt)+" W"

Assignment 1_Deadline 26 Sept 2017/assignment1_step2_riva.py

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+#ASSIGNMENT 1
+
+H = 3 #height of the wall
+W = 5 #width of the wall
+ht = 0.25 #total height of the unit
+hb = 0.22 #height of the brick
+hp = 0.015 #height of the plaster
+wf = 0.03 #width of the foam
+wp = 0.02 #width of the plaster layers
+wb = 0.16 #width of the brick
+k1 = float (raw_input("enter the thermal conductivity of the foam in W/(degC*m) "))#foam conduction heat transfer
+k2 = float (raw_input("enter the thermal conductivity of the plaster in W/(degC*m) ")) #plaster conduction heat transfer
+k3 = float (raw_input("enter the thermal conductivity of the brick in W/(degC*m) ")) #brick conduction heat transfer
+h1 = float (raw_input("enter the internal convenction heat transfer W/(degC*m^2) "))#inside convenction heat trasfer
+h2 = float (raw_input("enter the external convenction heat tranfer W/(degC*m^2) "))#outside convenction heat trasfer
+t1 = float (raw_input("enter the internal temperature in degC ")) #temperature in
+t2 = float (raw_input("enter the external temperature in degC ")) #temperature out
+
+#Res 
+Rconv = 1/(h1*ht*1)
+R1 = wf/(k1*ht*1) #foam Res
+R2 = R6 = wp/(k2*ht*1) # the two plaster side res
+R3 = R5 = wb/(k2*hp*1) # Plaster center Res
+R4 = wb/(k3*hb*1) # Brick Res
+R0 = 1/(h2*ht*1)  #second convention res
+
+Rp = ( (1/R3) + (1/R4) + (1/R5) )
+RP = 1/Rp #sum of the three res in the middle, they are in parallel
+
+Rt = Rconv+R1+R2+RP+R6+R0
+
+Q = (t1-(t2))/Rt #heat transfer through the wall
+s = (ht*1) #surface area in m^2
+Q1 = Q/s #heat transfer per m^2 area
+A = H * W #total area
+
+Qt = Q1*A
+
+
+print"The amount of heat transfer of the entire wall is "+str (Qt)+" degC/W"
+print"The amount of thermal resistence of the brick is "+str (Rt)+" W"

Assignment 2 Deadline Oct 3rd 2017/Assignment2_step1_Genco.py

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+#determination of the total thermal resistance and the heat transfer rate throw a Composite Wall
+
+H = 3 #height of the wall
+W = 5 #width of the wall
+t1 = 20 #temperature inside
+t2 = -10 #temperature outside
+ht = 0.25 #total height of the unit
+hb = 0.22 #height of the brick
+hp = 0.015 #height of the plaster
+wf = 0.03 #width of the foam
+wp = 0.02 #width of the plaster layers
+wb = 0.16 #width of the brick
+k1 = 0.026 #foam conduction heat transfer
+k2 = 0.22 #plaster conduction heat transfer
+k3 = 0.72 #brick conduction heat transfer
+h1 = 10 #inside convenction heat trasfer
+h2 = 25 #outside convenction heat trasfer
+
+#Resistence 
+Rconv = [0.25,10]
+R1 = [0.25, 0.03, 0.026] #foam Resistence
+R2 = R6 = [0.25,0.02,0.22] # the two plaster side resistence
+R3 = R5 = [0.015,0.16,0.22]  # Plaster center Resistence
+R4 = [0.22,0.16,0.72]     # Brick Resistence
+R0 = [0.25,25]             #second convention resistence
+
+series = [R1,R2,R3]
+parallel = [R3,R5,R4]
+convseries = [Rconv,R0]
+
+conv = 0
+for anyelement in convseries:
+    A = anyelement[0]
+    h = anyelement[1]
+    Rconv = 1/(A*h)
+CONVENCTION = conv + Rconv
+
+serie = 0
+for aanyelement in series:
+    A1 = aanyelement[0]
+    h1 = aanyelement[1]
+    k1= aanyelement[2]
+    Rconv = h1/(A1*k1)
+SERIES = serie + Rconv
+
+paral= 0
+for anyelement in parallel:
+    A2 = anyelement[0]
+    h2 = anyelement[1]
+    k2 = anyelement[2]
+    Rpar = h2/(A2*k2)
+    Rparal = paral + 1/Rpar
+PARALLELL = 1/Rparal
+
+RTOT= PARALLELL + CONVENCTION + SERIES
+
+
+print"The amount of thermal resistence of the brick is "+str (RTOT)+" W"

Assignment 2 Deadline Oct 3rd 2017/Assignment2_step2_Genco.py

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+#determination of the total thermal resistance and the heat transfer rate throw a Composite Wall
+
+H = 3 #height of the wall
+W = 5 #width of the wall
+t1 = 20 #temperature inside
+t2 = -10 #temperature outside
+ht = 0.25 #total height of the unit
+hb = 0.22 #height of the brick
+hp = 0.015 #height of the plaster
+wf = 0.03 #width of the foam
+wp = 0.02 #width of the plaster layers
+wb = 0.16 #width of the brick
+k1 = 0.026 #foam conduction heat transfer
+k2 = 0.22 #plaster conduction heat transfer
+k3 = 0.72 #brick conduction heat transfer
+h1 = 10 #inside convenction heat trasfer
+h2 = 25 #outside convenction heat trasfer
+
+#Resistence 
+Rconv = {"total height of the unit":0.25,"convenction heat trasfer":10}
+R1 = {"name":"foam","area":0.25,"lenght": 0.03,"k":0.026} 
+R2 = {"name":"plaster series","area":0.25,"lenght":0.02,"k":0.22} 
+R6 = {"name":"plaster series1","area":0.25,"lenght":0.02,"k":0.22}
+R3 = {"name":"plaster parallel","area":0.015,"lenght":0.16,"k":0.22}
+R5 = {"name":"plaster parallel1","area":0.015,"lenght":0.16,"k":0.22}  
+R4 = {"area":0.22,"lenght":0.16,"k":0.72}     
+R0 = {"total height of the unit":0.25,"convenction heat trasfer":25}             
+series = [R1,R2,R3]
+parallel = [R3,R5,R4]
+convseries = [Rconv,R0]
+
+conv = 0
+for anyelement in convseries:
+    A = anyelement["total height of the unit"]
+    h = anyelement["convenction heat trasfer"]
+    Rconv = 1/(A*h)
+CONVENCTION = conv + Rconv
+
+serie = 0
+for anyelement in series:
+    A1 = anyelement["area"]
+    h1 = anyelement["lenght"]
+    k1= anyelement["k"]
+    Rconv = h1/(A1*k1)
+SERIES = serie + Rconv
+
+paral= 0
+for aanyelement in parallel:
+    A2= aanyelement["area"]
+    h2 = aanyelement["lenght"]
+    k2 = aanyelement["k"]
+    Rpar = h2/(A2*k2)
+    Rparal = paral + 1/Rpar
+PARALLELL = 1/Rparal
+
+RTOT= PARALLELL + CONVENCTION + SERIES
+
+
+print"The amount of thermal resistence of the brick is "+str (RTOT)+" W"

Assignment 2 Deadline Oct 3rd 2017/assignment2_step1_riva.py

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+#ASSIGNMENT 2
+
+H = 3 #height of the wall
+W = 5 #width of the wall
+t1 = 20 #temperature inside
+t2 = -10 #temperature outside
+ht = 0.25 #total height of the unit
+hb = 0.22 #height of the brick
+hp = 0.015 #height of the plaster
+wf = 0.03 #width of the foam
+wp = 0.02 #width of the plaster layers
+wb = 0.16 #width of the brick
+k1 = 0.026 #foam conduction heat transfer
+k2 = 0.22 #plaster conduction heat transfer
+k3 = 0.72 #brick conduction heat transfer
+h1 = 10 #inside convenction heat trasfer
+h2 = 25 #outside convenction heat trasfer
+
+#Res
+Rconv = [0.25,10]
+R1 = [0.25, 0.03, 0.026]  #foam Res
+R2 = R6 = [0.25,0.02,0.22]  #the two plaster side res
+R3 = R5 = [0.015,0.16,0.22]  #Plaster center Res
+R4 = [0.22,0.16,0.72]     #Brick Res
+R0 = [0.25,25]             #second convention res
+
+series = [R1,R2,R3]
+parallel = [R3,R5,R4]
+convseries = [Rconv,R0]
+
+conv = 0
+for anyelement in convseries:
+    A = anyelement[0]
+    h = anyelement[1]
+    Rconv = 1/(A*h)
+CONVENCTION = conv + Rconv
+
+serie = 0
+for aanyelement in series:
+    A_ = aanyelement[0]
+    h_ = aanyelement[1]
+    k_= aanyelement[2]
+    Rconv = h_/(A_*k_)
+SERIES = serie + Rconv
+
+paral= 0
+for anyelement in parallel:
+    A__ = anyelement[0]
+    h__ = anyelement[1]
+    k__ = anyelement[2]
+    Rpar = h__/(A__*k__)
+    Rparal = paral + 1/Rpar
+PARALLELL = 1/Rparal
+
+RTOT= PARALLELL + CONVENCTION + SERIES
+
+
+print"The amount of thermal resistence of the brick is "+str (RTOT)+" W"