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Original file line number Diff line number Diff line change
@@ -0,0 +1,4 @@
<?xml version="1.0" encoding="UTF-8"?><sqlb_project><db path="Baruni Prabaharan Assignment 1.db" readonly="0" foreign_keys="0" case_sensitive_like="0" temp_store="0" wal_autocheckpoint="1000" synchronous="2"/><attached/><window><main_tabs open="structure browser pragmas query" current="1"/></window><tab_structure><column_width id="0" width="300"/><column_width id="1" width="0"/><column_width id="2" width="100"/><column_width id="3" width="419"/><column_width id="4" width="0"/><expanded_item id="0" parent="1"/><expanded_item id="1" parent="1"/><expanded_item id="2" parent="1"/><expanded_item id="3" parent="1"/></tab_structure><tab_browse><table title="assignment1" custom_title="0" dock_id="1" table="4,11:mainassignment1"/><dock_state state="000000ff00000000fd00000001000000020000033b00000276fc0100000001fb000000160064006f0063006b00420072006f007700730065003101000000000000033b0000012400ffffff000002580000000000000004000000040000000800000008fc00000000"/><default_encoding codec=""/><browse_table_settings><table schema="main" name="assignment1" show_row_id="0" encoding="" plot_x_axis="" unlock_view_pk="_rowid_" freeze_columns="0"><sort/><column_widths><column index="1" value="725"/></column_widths><filter_values/><conditional_formats/><row_id_formats/><display_formats/><hidden_columns/><plot_y_axes/><global_filter/></table></browse_table_settings></tab_browse><tab_sql><sql name="SQL 1*">SELECT *
FROM customer_purchases
WHERE product_id IN (4, 9);
</sql><current_tab id="0"/></tab_sql></sqlb_project>
Expand Down
89 changes: 83 additions & 6 deletions 02_activities/assignments/Cohort_8/assignment1.sql
Original file line number Diff line number Diff line change
Expand Up @@ -4,17 +4,22 @@

--SELECT
/* 1. Write a query that returns everything in the customer table. */

SELECT * FROM customer;


/* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table,
sorted by customer_last_name, then customer_first_ name. */
SELECT * FROM customer
ORDER BY customer_last_name, customer_first_name
limit 10;



--WHERE
/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */

SELECT *
FROM customer_purchases
WHERE product_id IN (4, 9);


/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty),
Expand All @@ -23,29 +28,65 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
2. one condition using BETWEEN
*/
-- option 1
SELECT *, (QUANTITY*cost_to_customer_per_qty) AS PRICE
FROM customer_purchases
WHERE customer_id >= 8 AND customer_id <= 10;


-- option 2

-- option 2

SELECT *, (QUANTITY*cost_to_customer_per_qty) AS PRICE
FROM customer_purchases
WHERE customer_id BETWEEN 8 AND 10;

--CASE
/* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz.
Using the product table, write a query that outputs the product_id and product_name
columns and add a column called prod_qty_type_condensed that displays the word “unit”
if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */

SELECT
product_id,
product_name,
CASE
WHEN product_qty_type = 'unit' THEN 'unit'
ELSE 'bulk'
END AS prod_qty_type_condensed
FROM product;


/* 2. We want to flag all of the different types of pepper products that are sold at the market.
add a column to the previous query called pepper_flag that outputs a 1 if the product_name
contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
SELECT
product_id,
product_name,
CASE
WHEN product_qty_type = 'unit' THEN 'unit'
ELSE 'bulk'
END AS prod_qty_type_condensed
,CASE
WHEN LOWER(product_name) LIKE '%pepper%' THEN 1
ELSE 0
END AS pepper_flag
FROM product;




--JOIN
/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the
vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
SELECT
v.vendor_id,
v.vendor_name,
vba.market_date,
vba.booth_number
FROM vendor AS v
INNER JOIN vendor_booth_assignments AS vba
ON v.vendor_id = vba.vendor_id
ORDER BY v.vendor_name, vba.market_date;




Expand All @@ -55,6 +96,13 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
-- AGGREGATE
/* 1. Write a query that determines how many times each vendor has rented a booth
at the farmer’s market by counting the vendor booth assignments per vendor_id. */
SELECT
vendor_id,
COUNT(*) AS booth_rental_count
FROM vendor_booth_assignments
GROUP BY vendor_id
ORDER BY booth_rental_count DESC;




Expand All @@ -63,7 +111,17 @@ sticker to everyone who has ever spent more than $2000 at the market. Write a qu
of customers for them to give stickers to, sorted by last name, then first name.

HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */

SELECT
c.customer_id,
c.customer_first_name,
c.customer_last_name,
SUM(cp.quantity * cp.cost_to_customer_per_qty) AS total_spent
FROM customer_purchases AS cp
INNER JOIN customer AS c
ON cp.customer_id = c.customer_id
GROUP BY c.customer_id, c.customer_first_name, c.customer_last_name
HAVING SUM(cp.quantity * cp.cost_to_customer_per_qty) > 2000
ORDER BY c.customer_last_name, c.customer_first_name;


--Temp Table
Expand All @@ -77,6 +135,13 @@ When inserting the new vendor, you need to appropriately align the columns to be
-> To insert the new row use VALUES, specifying the value you want for each column:
VALUES(col1,col2,col3,col4,col5)
*/
CREATE TABLE temp.new_vendor AS
SELECT *
FROM vendor;
INSERT INTO temp.new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
VALUES (10, 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal');





Expand All @@ -85,7 +150,11 @@ VALUES(col1,col2,col3,col4,col5)

HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month
and year are! */

SELECT
customer_id,
strftime('%m', MARKET_date) AS month,
strftime('%Y', market_date) AS year
FROM customer_purchases;


/* 2. Using the previous query as a base, determine how much money each customer spent in April 2022.
Expand All @@ -94,3 +163,11 @@ Remember that money spent is quantity*cost_to_customer_per_qty.
HINTS: you will need to AGGREGATE, GROUP BY, and filter...
but remember, STRFTIME returns a STRING for your WHERE statement!! */

SELECT
customer_id,
SUM(quantity * cost_to_customer_per_qty) AS total_spent
FROM customer_purchases
WHERE strftime('%m', market_date) = '04'
AND strftime('%Y', market_date) = '2022'
GROUP BY customer_id;