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52 changes: 52 additions & 0 deletions BOJ/[20920] 영단어 암기는 괴로워/nkw601/Main.java
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import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;
import java.util.StringTokenizer;

public class Main {
private static int N, M; // 지문에 나오는 단어 수, 외울 단어의 길이 기준(M 이상만 외움)
private static HashMap<String, Integer> words;
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
StringTokenizer st = new StringTokenizer(br.readLine());
StringBuilder sb = new StringBuilder();
// 입력, 초기화
N = Integer.parseInt(st.nextToken());
M = Integer.parseInt(st.nextToken());
words = new HashMap<>();

for(int i = 0; i < N; i++) {
String word = br.readLine();
// 길이가 M 이상일 때에만 외움
if(word.length() >= M) {
// getOrDefault
words.put(word, words.getOrDefault(word, 0) + 1);
}
}

// 자주 나오는 단어면 앞에
// 단어의 길이가 길면 앞에
// 알파벳 사전 순으로 앞이면 앞에
ArrayList<String> wordsList = new ArrayList<>(words.keySet());
Collections.sort(wordsList, (o1, o2) -> {
int f1 = words.get(o1), f2 = words.get(o2);
if (f1 != f2) return Integer.compare(f2, f1); // 빈도
int l1 = o1.length(), l2 = o2.length();
if (l1 != l2) return Integer.compare(l2, l1); // 길이
return o1.compareTo(o2); // 사전순
});


for(String word : wordsList) {
sb.append(word).append("\n");
}

System.out.println(sb);

}

}
55 changes: 55 additions & 0 deletions BOJ/[2512] 예산/nkw601/Main.java
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import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class Main {
private static int N, M;
private static int[] budgets;

public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
StringTokenizer st;

N = Integer.parseInt(br.readLine());
budgets = new int[N];

st = new StringTokenizer(br.readLine());
int maxReq = 0;
long sum = 0;
for (int i = 0; i < N; i++) {
budgets[i] = Integer.parseInt(st.nextToken());
sum += budgets[i];
if (budgets[i] > maxReq) maxReq = budgets[i];
}

M = Integer.parseInt(br.readLine());

if (sum <= M) {
System.out.println(maxReq);
return;
}

int low = 0;
int high = maxReq;
int ans = 0;

while (low <= high) {
int mid = (low + high) / 2;
long s = 0;

for (int b : budgets) {
s += (b > mid) ? mid : b;
}

if (s <= M) {
ans = mid;
low = mid + 1;
} else {
high = mid - 1;
}
}

System.out.println(ans);
}
}
85 changes: 85 additions & 0 deletions BOJ/[5972] 택배 배송/nkw601/Main.java
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import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.PriorityQueue;
import java.util.StringTokenizer;

public class Main {
private static int N, M;
private static int[] stovers; // stovers: i번째 헛간까지 도착하는 최소 여물 수
private static ArrayList<int[]>[] barns;
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
StringTokenizer st = new StringTokenizer(br.readLine());

N = Integer.parseInt(st.nextToken());
M = Integer.parseInt(st.nextToken());

// 초기화
stovers = new int[N + 1];
Arrays.fill(stovers, Integer.MAX_VALUE);
barns = new ArrayList[N + 1];
for(int i = 1; i <= N; i++) {
barns[i] = new ArrayList<>();
}

for(int i = 0; i < M; i++) {
st = new StringTokenizer(br.readLine());
int a = Integer.parseInt(st.nextToken());
int b = Integer.parseInt(st.nextToken());
int c = Integer.parseInt(st.nextToken());

// 인접리스트 만들기
barns[a].add(new int[] {b, c});
barns[b].add(new int[] {a, c});
}

dijkstra(1, N);
System.out.println(stovers[N]);
}


private static void dijkstra(int start, int end) {
PriorityQueue<int[]> pq = new PriorityQueue<>((o1, o2) -> Integer.compare(o1[1], o2[1]));
stovers[start] = 0;
pq.offer(new int[] {start, 0});

while(!pq.isEmpty()) {
int[] cur = pq.poll();

int curBarn = cur[0];
int curWei = cur[1];

if(curWei > stovers[curBarn]) continue; // 방문처리

for(int[] next : barns[curBarn]) {
int nextBarn = next[0];
int nextWei = next[1] + curWei;

if(nextWei < stovers[nextBarn]) {
pq.offer(new int[] {nextBarn, nextWei});
stovers[nextBarn] = nextWei;
}
}
}
}
}
/*
* 입력
* N M
* M: A_i B_i C_i
*
* 출력
* 농부 현서가 가져가야하는 최소 여물
*
* 이해
* N개의 헛간, M개의 양방향 길
* 각각의 길의 가중치 C(소 수)
*
* 헛간 1 -> 헛간 N
*
* 생각
* 최단 거리 with 가중치 -> 다익스트라
*/