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[mintheon] Week 09 #990

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Feb 9, 2025
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13 changes: 13 additions & 0 deletions find-minimum-in-rotated-sorted-array/mintheon.java
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해당 문제의 경우 시간 복잡도를 O(n) 으로 하셔도 괜찮지만, 조건 상 O(log n) 으로 되어있기 때문에 다시 한번 풀이에 도전해 보셔도 괜찮을것 같아요 :)

Original file line number Diff line number Diff line change
@@ -0,0 +1,13 @@
class Solution {
// 시간복잡도: O(n)
// 공간복잡도: O(1)
public int findMin(int[] nums) {
for(int i = 1; i < nums.length; i++) {
if(nums[i - 1] > nums[i]) {
return nums[i];
}
}

return nums[0];
}
}
28 changes: 28 additions & 0 deletions linked-list-cycle/mintheon.java
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LinkedList 의 특징을 잘 살려서 풀이 해 주신것 같습니다!
이후에도 비슷한 문제가 나올 예정입니다!

Original file line number Diff line number Diff line change
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/**
* Definition for singly-linked list.
* class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
//시간복잡도: O(n)
//공간복잡도: O(1)
public class Solution {
public boolean hasCycle(ListNode head) {
ListNode slow = head;
ListNode fast = head;

while(fast != null && fast.next != null) {
slow = slow.next;
fast = fast.next.next;

if(slow == fast) return true;
}

return false;
}
}