[nancyel] WEEK 01 solutions

contains-duplicate/nancyel.ts

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+/**
+ * time complexity: O(n)
+ * space complexity: O(n)
+ */
+function containsDuplicate(nums: number[]): boolean {
+  const seen = new Set();
+  for (let num of nums) {
+    if (seen.has(num)) {
+      return true;
+    }
+    seen.add(num);
+  }
+  return false;
+}

house-robber/nancyel.ts

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+/**
+ * time complexity: O(n) - iterate over a loop
+ * space complexity: O(n) - dp array
+ *
+ * comment: initial naive implementation: simple odd/even alternation, which may return result that is "accidentally correct."
+ */
+function rob(nums: number[]): number {
+  // early return
+  if (nums.length === 0) return 0;
+  if (nums.length === 1) return nums[0];
+
+  const dp: number[] = new Array(nums.length);
+  dp[0] = nums[0];
+  dp[1] = Math.max(nums[0], nums[1]);
+
+  for (let i = 2; i < nums.length; i++) {
+    // select either 1) current + best from 2 houses ago or 2) skip current, best from previous
+    dp[i] = Math.max(nums[i] + dp[i - 2], dp[i - 1]);
+  }
+
+  return dp[nums.length - 1]; // max money from all houses
+}

longest-consecutive-sequence/nancyel.ts

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+/**
+ * requirement: return result in linear time (O(n))
+ */
+function longestConsecutive(nums: number[]): number {
+  if (nums.length === 0) return 0;
+
+  const numSet = new Set(nums); // O(1) lookups
+  let maxLength = 0;
+
+  for (const num of numSet) {
+    // key: determine the "start" of a consecutive sequence.
+    // approach: if num - 1 doesn't exist in the set → num is the start of a sequence.
+    if (!numSet.has(num - 1)) {
+      let currentNum = num;
+      let currentLength = 1;
+
+      // count consecutive numbers
+      while (numSet.has(currentNum + 1)) {
+        currentNum++;
+        currentLength++;
+      }
+
+      maxLength = Math.max(maxLength, currentLength);
+    }
+  }
+  return maxLength;
+}

top-k-frequent-elements/nancyel.ts

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+/**
+ * time complexity: O(n + m log m),
+ *   n = length of input array
+ *   m = number of unique elements (m ≤ n)
+ * space complexity: O(m)
+ */
+
+function topKFrequent(nums: number[], k: number): number[] {
+  const freqMap = new Map<number, number>();
+
+  // Count frequencies using a map: O(n)
+  for (const num of nums) {
+    freqMap.set(num, (freqMap.get(num) || 0) + 1);
+  }
+
+  // Extract the top k elements
+  return Array.from(freqMap.entries()) // O(m)
+    .sort(([, a], [, b]) => b - a) // O(m log m)
+    .slice(0, k)
+    .map(([num]) => num); // extract the keys only
+}

two-sum/nancyel.ts

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+/**
+ * Time Complexity: O(n) (using a single pass with a hash map)
+ * (If a nested loop was used, it would be O(n^2))
+ */
+function twoSum(nums: number[], target: number): number[] {
+  const numAndIndex = new Map<number, number>();
+
+  for (let i = 0; i < nums.length; i++) {
+    const diff = target - nums[i];
+
+    if (numAndIndex.has(diff)) {
+      return [numAndIndex.get(diff)!, i];
+    }
+
+    numAndIndex.set(nums[i], i);
+  }
+
+  return [];
+}