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bumprelease functionality #382
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You pass it as option on the command line. Theoretically we could teach it to look in your
You are calling
It looks like somehow a wrong version ends up in here. We use this code to parse a version, which looks like it works both with and without a
It would fail when we somehow pass
Are you familiar with Otherwise, tell bumpversion to print debugging info:
It should increase it to 2.0.0.
Without the quotes. In
But I played around a bit in a test repository, also with the Oh, and the version of |
I actually set a print command there at 108. and its doent print the parse_version. Seems like prse_version is blank somehow
Verbose output:
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Verbose output
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You are printing the function, not the outcome of the function. Can you print the following instead?
I expect one of the last two lines to fail. |
6.22.2 print(parse_version(minimum_version)) produces the below error as minimum_version(seen above) in NONE File "/opt/conda/bin/bumpversion", line 8, in |
So the problem is with calling
When called with I can change |
Hi Team,
I am not sure how bumprelease feature works. Does it read "--breaking" from git log and detemines that it has to bump the release to next major release or its more like passing it via cli "bumprelease --breaking".
secondly. if my tags are like v1.0.1 and if I do bumprelease --version. it fails.
When current tag is v1.3.1 and version is setup.py is 1.3.1.. Should bumpversion --breaking, increase it to 2.0.0 instead of failing
Last tag: v1.3.1
Current version: 1.3.1
and we do tagging as v1.0.1 in our project, so what should exactly go in setup.cfg to take care of this format
tag-format = v'{version}' or something else
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