solution.py

# In a small town the population is p0 = 1000 at the beginning of a year.
# The population regularly increases by 2 percent per year
# and moreover 50 new inhabitants per year come to live in the town.
# How many years does the town need to see its population greater or equal to p = 1200 inhabitants?

# At the end of the first year there will be:
# 1000 + 1000 * 0.02 + 50 => 1070 inhabitants

# At the end of the 2nd year there will be:
# 1070 + 1070 * 0.02 + 50 => 1141 inhabitants (number of inhabitants is an integer)

# At the end of the 3rd year there will be:
# 1141 + 1141 * 0.02 + 50 => 1213

# It will need 3 entire years.
# More generally given parameters:

# p0, percent, aug (inhabitants coming or leaving each year), p (population to surpass)
# the function nb_year should return n number of entire years needed to get a population greater or equal to p.
# aug is an integer, percent a positive or null number, p0 and p are positive integers (> 0)

# Examples:
# nb_year(1500, 5, 100, 5000) -> 15
# nb_year(1500000, 2.5, 10000, 2000000) -> 10
# Note: Don't forget to convert the percent parameter as a percentage in the body of your function: ' \
#          'if the parameter percent is 2 you have to convert it to 0.02.


def nb_year(p0, percent, aug, p):
    count = 0
    while p0 < p:
        p0 += int(p0 * percent / 100 + aug)
        count += 1

    return count