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p2.cpp
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#include <iostream>
#include <fstream>
#include <vector>
#include <algorithm>
class Task {
public:
void solve() {
read_input();
print_output(get_result());
}
private:
long long N, k;
std::vector<long long> sir;
long long solution;
void read_input() {
std::ifstream fin("p2.in");
fin >> N >> k;
long long n;
for (int i = 0; i < N; i++) {
fin >> n;
sir.push_back(n);
std::cout << n << " ";
}
fin.close();
}
// Comparator, sortam in ordine descrescatoare
static bool comparator(long long ob1, long long ob2) {
return (ob1 > ob2);
}
long long findSolution(const std::vector<long long> &sir) {
std::vector<std::vector<long long>> dp
(k + 1, std::vector<long long>(sir.size()));
printf("\n ");
// Completam prima linie a matricei dp
long long sum_Tzugu = 0;
long long sum_Ritza = 0;
long long i;
for (i = 0; i < sir.size(); ++i) {
if (!(i & 1)) {
sum_Tzugu += sir[i];
} else {
sum_Ritza += sir[i];
}
dp[0][i] = sum_Tzugu - sum_Ritza;
}
// Continuam sa completam si celelalte linii (1 -> k)
for (long long i = 1; i <= k; i++) {
unsigned l;
// Eliminam elemente pe fiecare linie pana la k
// Adica punem 0 pe primele i pozitii de pe linia i
for (l = 0; l < i; l++) {
dp[i][l] = 0;
}
// Completez in continuare, dupa ce am eliminat i elemente
for (unsigned j = l; j < sir.size(); j++) {
long long number;
if ((j - i) % 2 == 0) {
// Daca e pozitie para, adun
number = dp[i][j - 1] + sir[j];
} else {
// Daca e pozitie impara, scad
number = dp[i][j - 1] - sir[j];
}
dp[i][j] = std::max(number, dp[i - 1][j - 1]);
}
}
return dp[k][sir.size() - 1];
}
long long get_result() {
// Sortam in ordine descrescatoare
std::sort(sir.begin(), sir.end(), comparator);
solution = findSolution(sir);
return solution;
}
void print_output(long long result) {
std::ofstream fout("p2.out");
fout << result;
fout.close();
}
};
int main() {
Task task;
task.solve();
return 0;
}