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57.Insert.cs
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// 57. Insert Interval
// You are given an array of non-overlapping intervals intervals where intervals[i] = [starti, endi]
// represent the start and the end of the ith interval and intervals is sorted in ascending order by
// starti. You are also given an interval newInterval = [start, end] that represents the start and end
// of another interval.
// Insert newInterval into intervals such that intervals is still sorted in ascending order by starti
// and intervals still does not have any overlapping intervals (merge overlapping intervals if necessary).
// Return intervals after the insertion.
// Note that you don't need to modify intervals in-place. You can make a new array and return it.
// Example 1:
// Input: intervals = [[1,3],[6,9]], newInterval = [2,5]
// Output: [[1,5],[6,9]]
// Example 2:
// Input: intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]
// Output: [[1,2],[3,10],[12,16]]
// Explanation: Because the new interval [4,8] overlaps with [3,5],[6,7],[8,10].
// Constraints:
// 0 <= intervals.length <= 104
// intervals[i].length == 2
// 0 <= starti <= endi <= 105
// intervals is sorted by starti in ascending order.
// newInterval.length == 2
// 0 <= start <= end <= 105
public class Solution {
public int[][] Insert(int[][] intervals, int[] newInterval) {
List<int[]> result = new();
int i = 0;
// Add all intervals that end before the new interval starts
while (i < intervals.Length && intervals[i][1] < newInterval[0]) {
result.Add(intervals[i]);
i++;
}
// Merge intervals that overlap with the new interval
while (i < intervals.Length && intervals[i][0] <= newInterval[1]) {
newInterval[0] = Math.Min(newInterval[0], intervals[i][0]);
newInterval[1] = Math.Max(newInterval[1], intervals[i][1]);
i++;
}
// Add the merged new interval
result.Add(newInterval);
// Add all remaining intervals
while (i < intervals.Length) {
result.Add(intervals[i]);
i++;
}
return result.ToArray();
}
}