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Copy path482.LicenseKeyFormatting.cs
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482.LicenseKeyFormatting.cs
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// 482. License Key Formatting
// You are given a license key represented as a string s that consists of only alphanumeric characters
// and dashes. The string is separated into n + 1 groups by n dashes. You are also given an integer k.
// We want to reformat the string s such that each group contains exactly k characters,
// except for the first group, which could be shorter than k but still must contain at least one character.
// Furthermore, there must be a dash inserted between two groups, and you should convert all lowercase letters to uppercase.
// Return the reformatted license key.
// Example 1:
// Input: s = "5F3Z-2e-9-w", k = 4
// Output: "5F3Z-2E9W"
// Explanation: The string s has been split into two parts, each part has 4 characters.
// Note that the two extra dashes are not needed and can be removed.
// Example 2:
// Input: s = "2-5g-3-J", k = 2
// Output: "2-5G-3J"
// Explanation: The string s has been split into three parts, each part has 2 characters except the first part as it could be shorter as mentioned above.
// Constraints:
// 1 <= s.length <= 105
// s consists of English letters, digits, and dashes '-'.
// // 1 <= k <= 104
public class Solution {
public string LicenseKeyFormatting(string s, int k) {
s = s.Replace("-", "").ToUpper();
//intution: insert '-' from the end of the string with k interval.
var sb = new StringBuilder(s);
for(int i = s.Length - k; i > 0; i -= k){
sb.Insert(i, '-');
}
return sb.ToString();
}
}
public class Solution {
public string LicenseKeyFormatting(string s, int k) {
s = s.Replace("-", "").ToUpper();
string res = "";
for(int i = s.Length; i >= 0; i -= k){
string temp = "";
for(int j = Math.Max(i - k, 0); j < i; j++ ){
temp += s[j];
}
res = temp + res;
if(i - k > 0)
res = "-" + res;
}
return res;
}
}