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| 1 | +#include <iostream> |
| 2 | +#include <cstring> |
| 3 | +#include <cstdio> |
| 4 | +#include <map> |
| 5 | +#include <algorithm> |
| 6 | +#include <vector> |
| 7 | +#include <climits> |
| 8 | +#include <utility> |
| 9 | +#include <cmath> |
| 10 | +using namespace std; |
| 11 | + |
| 12 | + |
| 13 | +#define MAX 100000 |
| 14 | +const int MAX_SEG = 262144+1; |
| 15 | +int A[MAX + 1], S[MAX + 2], lo[MAX + 1 ], hi[MAX + 1]; |
| 16 | +int M[MAX_SEG]; |
| 17 | + |
| 18 | +int N, Q; |
| 19 | + |
| 20 | +int built(int node, int b, int e){ |
| 21 | + if(b == e) return M[node] = A[b]; |
| 22 | + int mid = (b+e)/2; |
| 23 | + int left = node << 1; |
| 24 | + int right = left + 1; |
| 25 | + |
| 26 | + M[left] = built( left, b, mid ); |
| 27 | + M[right] = built( right , mid + 1, e ); |
| 28 | + |
| 29 | + return M[node] = max(M[left], M[right]); |
| 30 | + |
| 31 | + |
| 32 | +} |
| 33 | +int query(int node, int b, int e, int i, int j){ |
| 34 | + if(b >= i && e <= j) return M[node]; |
| 35 | + if(b > j || e < i) return -1; |
| 36 | + |
| 37 | + int left = query(2*node, b, (b + e)/2, i, j); |
| 38 | + int right = query(2*node+1, (b + e)/2 + 1, e, i, j); |
| 39 | + if(left == -1) return right; |
| 40 | + if(right == -1 )return left; |
| 41 | + return max(left, right); |
| 42 | + |
| 43 | +} |
| 44 | +int main(){ |
| 45 | + //freopen("input.txt", "r", stdin); |
| 46 | + int st, en; |
| 47 | + while(scanf("%d", &N) == 1&& N){ |
| 48 | + scanf("%d", &Q); |
| 49 | + for(int i = 1; i <= N; i++) |
| 50 | + scanf("%d", &S[i]); |
| 51 | + |
| 52 | + { |
| 53 | + st = 1; |
| 54 | + S[N+1] = INT_MIN; |
| 55 | + } |
| 56 | + for(int i = 1; i <= N + 1; i++){ |
| 57 | + |
| 58 | + if(S[i] != S[i+1]){ |
| 59 | + int width = i - st + 1; |
| 60 | + for(int j = st; j <= i; j++){ |
| 61 | + A[j] = width; |
| 62 | + lo[j] = st; |
| 63 | + hi[j] = i; |
| 64 | + } |
| 65 | + st = i + 1; |
| 66 | + } |
| 67 | + } |
| 68 | + |
| 69 | + |
| 70 | + int i, j, ans; |
| 71 | + built(1, 1, N); |
| 72 | + while(Q--){ |
| 73 | + scanf("%d %d", &st, &en); |
| 74 | + ans = 0; |
| 75 | + i = hi[st] + 1; |
| 76 | + j = lo[en] - 1; |
| 77 | + |
| 78 | + if(hi[st] <= en) ans = max(hi[st] - st +1, ans); |
| 79 | + else ans = max(ans, en - st + 1); |
| 80 | + |
| 81 | + if(lo[en] >= st) ans = max(en - lo[en] + 1, ans); |
| 82 | + else ans = max(ans, en - st + 1); |
| 83 | + |
| 84 | + if(i < j) ans = max(query(1, 1, N, i, j), ans); |
| 85 | + printf("%d\n", ans); |
| 86 | + } |
| 87 | + } |
| 88 | + return 0; |
| 89 | +} |
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