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| I'm looking to create a new route for my app, which will take a  Presumably I can parse the parameter by separating out the comma-separated values like so: But I was wondering if there was a built-in way/better to do this with  Thanks a lot! | 
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| Hi @mergesort, the second argument of  So you can create a custom conversion for turning a string into an array of  struct CommaSeparatedURLs: Conversion {
  func apply(_ input: Substring) throws -> [URL] {
    input.split(separator: ",").compactMap { URL(string: String($0)) }
  }
  func unapply(_ output: [URL]) throws -> Substring {
    output.map(\.absoluteString).joined(separator: ",")[...]
  }
}And then you can use this with  Field("links", CommaSeparatedURLs())And you can also add a  | 
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Hi @mergesort, the second argument of
Fieldis aConversion, which describes a way of transforming an input to an output and back into an input. It's similar to a parser, but it does not consume anything. It just transforms back-and-forth.So you can create a custom conversion for turning a string into an array of
URLs and back:And then you can use this with
Field:And …