-
Notifications
You must be signed in to change notification settings - Fork 1
/
Copy pathD.cpp
106 lines (89 loc) · 1.93 KB
/
D.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
#pragma GCC optimize "trapv"
#pragma GCC optimize("O3", "unroll-loops")
#pragma GCC target("avx2")
#include<bits/stdc++.h>
#define ll long long int
#define fab(a,b,i) for(int i=a;i<b;i++)
#define pb push_back
#define db double
#define mp make_pair
#define endl "\n"
#define f first
#define se second
#define all(x) x.begin(),x.end()
#define MOD 1000000007
#define vll vector<ll>
#define vi vector<int>
#define pii pair<int,int>
#define pll pair<ll,ll>
#define quick ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL)
ll add(ll x, ll y) {ll res = x + y; return (res >= MOD ? res - MOD : res);}
ll mul(ll x, ll y) {ll res = x * y; return (res >= MOD ? res % MOD : res);}
ll sub(ll x, ll y) {ll res = x - y; return (res < 0 ? res + MOD : res);}
ll power(ll x, ll y) {ll res = 1; x %= MOD; while (y) {if (y & 1)res = mul(res, x); y >>= 1; x = mul(x, x);} return res;}
ll mod_inv(ll x) {return power(x, MOD - 2);}
using namespace std;
const int N=2e5+5;
vector<ll> v[N];
vector<ll> topo;
ll a[N+1],b[N+1];
void dfs( int src,bool vis[])
{
vis[src]=1;
for( auto i: v[src])
{
if(!vis[i])
dfs(i,vis);
}
topo.pb(src);
}
int main()
{ quick;
#ifndef ONLINE_JUDGE
freopen("D:/sublime/input.txt", "r", stdin);
freopen("D:/sublime/output.txt", "w", stdout);
#endif
ll n;
cin>>n;
fab(1,n+1,i)
cin>>a[i];
fab(1,n+1,i)
cin>>b[i];
fab(1,n+1,i)
{
if(b[i]!=-1)
{
v[i].pb(b[i]);
}
}
bool vis[n+1];
fab(0,n+1,i)
vis[i]=0;
fab(1,n+1,i)
{
if(!vis[i])
dfs(i,vis);
}
reverse( all(topo));
ll ans=0;
vector<int> later,now;
fab(0,topo.size(),i)
{
ans+=a[topo[i]];
if(a[topo[i]]>=0 and b[topo[i]]!=-1)
{
a[b[topo[i]]]+=a[topo[i]];
now.pb(topo[i]);
}
else
later.pb(topo[i]);
}
reverse(all(later));
cout<<ans<<endl;
for(auto i: now)
cout<<i<<" ";
for(auto i: later)
cout<<i<<" ";
cerr << "time taken : " << (float)clock() / CLOCKS_PER_SEC << " secs" << endl;
return 0;
}