You are given two positive integers n
and limit
.
Return the total number of ways to distribute n
candies among 3
children such that no child gets more than limit
candies.
Example 1:
Input: n = 5, limit = 2 Output: 3 Explanation: There are 3 ways to distribute 5 candies such that no child gets more than 2 candies: (1, 2, 2), (2, 1, 2) and (2, 2, 1).
Example 2:
Input: n = 3, limit = 3 Output: 10 Explanation: There are 10 ways to distribute 3 candies such that no child gets more than 3 candies: (0, 0, 3), (0, 1, 2), (0, 2, 1), (0, 3, 0), (1, 0, 2), (1, 1, 1), (1, 2, 0), (2, 0, 1), (2, 1, 0) and (3, 0, 0).
Constraints:
1 <= n <= 50
1 <= limit <= 50
Related Topics:
Math, Combinatorics, Enumeration
Similar Questions:
Hints:
- Use three nested for loops to check all the triplets.
// OJ: https://leetcode.com/problems/distribute-candies-among-children-i
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(1)
class Solution {
public:
int distributeCandies(int n, int limit) {
int ans = 0;
for (int i = 0; i <= limit; ++i) {
ans += max(0, min(n - i, limit) - max(0, n - i - limit) + 1);
}
return ans;
}
};