diff --git a/02_activities/assignments/assignment1.sql b/02_activities/assignments/assignment1.sql
index 2e89fa7af..b33c278b9 100644
--- a/02_activities/assignments/assignment1.sql
+++ b/02_activities/assignments/assignment1.sql
@@ -5,21 +5,31 @@
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
 
-
+SELECT *
+FROM customer;
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
 
+SELECT*
+FROM customer
+ORDER BY  customer_last_name, customer_first_name
+LIMIT 10;
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 -- option 1
 
+SELECT *
+FROM customer_purchases
+WHERE product_id IN (4, 9)
 
 -- option 2
 
-
+SELECT *
+FROM customer_purchases
+WHERE product_id = 4 or product_id = 9;
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
 filtered by vendor IDs between 8 and 10 (inclusive) using either:
@@ -28,9 +38,17 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
 */
 -- option 1
 
+SELECT*,
+quantity*cost_to_customer_per_qty as price
+FROM customer_purchases
+WHERE vendor_id <= 8 AND vendor_id <= 10;
 
 -- option 2
 
+SELECT*,
+quantity*cost_to_customer_per_qty as price
+FROM customer_purchases
+WHERE vendor_id BETWEEN 8 AND 10;
 
 
 --CASE
@@ -39,19 +57,35 @@ Using the product table, write a query that outputs the product_id and product_n
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
 
+SELECT product_id, product_name,
+CASE
+	WHEN product_qty_type = 'unit' THEN 'unit'
+	ELSE 'bulk'
+END AS prod_qty_type_condensed
+FROM product;
 
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
 
-
+SELECT product_id, product_name,
+CASE WHEN product_qty_type = 'unit' THEN 'unit' ELSE 'bulk' END as product_qty_type_condensed,
+CASE WHEN product_name LIKE '%pepper%' THEN 1 ELSE 0 END as pepper_flag
+FROM product;
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
 
+SELECT
+vendor.vendor_id, vendor_name, market_date,
 
+FROM vendor 
+INNER JOIN vendor_booth_assignments 
+    ON vendor.vendor_id = vendor_booth_assignments.vendor_id
+ 
+ORDER BY vendor_name, market_date;
 
 
 /* SECTION 3 */
@@ -60,7 +94,10 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
 
+SELECT vendor_id, count(vendor_id) as num_times_rented
 
+FROM vendor_booth_assignments
+GROUP BY vendor_id;
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
 sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
@@ -68,6 +105,18 @@ of customers for them to give stickers to, sorted by last name, then first name.
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
+SELECT 
+customer_purchases.customer_id,
+customer.customer_first_name,
+customer.customer_last_name,
+SUM(quantity*cost_to_customer_per_qty) as total_cost
+
+FROM customer_purchases
+INNER JOIN customer
+    ON customer_purchases.customer_id=customer.customer_id
+GROUP BY customer_purchases.customer_id
+HAVING total_cost > 2000
+ORDER BY customer_last_name, customer_first_name;
 
 
 --Temp Table
@@ -82,7 +131,14 @@ When inserting the new vendor, you need to appropriately align the columns to be
 VALUES(col1,col2,col3,col4,col5) 
 */
 
+DROP TABLE IF EXISTS temp.new_vendor;
+
+CREATE TABLE temp.new_vendor AS
+SELECT *
+FROM vendor;
 
+INSERT INTO temp.new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
+VALUES (10, "Thomas's Superfood Store", 'Fresh Focused', 'Thomas', 'Rosenthal');
 
 -- Date
 /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
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