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[Bug] explicitly wrap non-list object as list for children property. #2

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@softmarshmallow

Description

@softmarshmallow

When anonymous widget assigns to children property, and it's non list but a single object. It still build as-is.

So,

Stack(
   children: Widget()
);

code something like above gets generated.

prevent this by wrapping incomming widget as array - [] for preventing this.

so expected code will be.

Stack(
   children: [Widget()]
);

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