README_CN.md

1662. 检查两个字符串数组是否相等

给你两个字符串数组 word1 和 word2 。如果两个数组表示的字符串相同，返回 true ；否则，返回 false 。

数组表示的字符串 是由数组中的所有元素 按顺序 连接形成的字符串。

示例 1:

输入: word1 = ["ab", "c"], word2 = ["a", "bc"]
输出: true
解释:
word1 表示的字符串为 "ab" + "c" -> "abc"
word2 表示的字符串为 "a" + "bc" -> "abc"
两个字符串相同，返回 true

示例 2:

输入: word1 = ["a", "cb"], word2 = ["ab", "c"]
输出: false

示例 3:

输入: word1  = ["abc", "d", "defg"], word2 = ["abcddefg"]
输出: true

提示:

• 1 <= word1.length, word2.length <= 103
• 1 <= word1[i].length, word2[i].length <= 103
• 1 <= sum(word1[i].length), sum(word2[i].length) <= 103
• word1[i] 和 word2[i] 由小写字母组成

题解 (Ruby)

1. 题解

# @param {String[]} word1
# @param {String[]} word2
# @return {Boolean}
def array_strings_are_equal(word1, word2)
  word1.join == word2.join
end

题解 (Rust)

1. 题解

impl Solution {
    pub fn array_strings_are_equal(word1: Vec<String>, word2: Vec<String>) -> bool {
        word1.concat() == word2.concat()
    }
}