README_CN.md

1470. 重新排列数组

给你一个数组 nums ，数组中有 2n 个元素，按 [x1,x2,...,xn,y1,y2,...,yn] 的格式排列。

请你将数组按 [x1,y1,x2,y2,...,xn,yn] 格式重新排列，返回重排后的数组。

示例 1:

输入: nums = [2,5,1,3,4,7], n = 3
输出: [2,3,5,4,1,7]
解释: 由于 x1=2, x2=5, x3=1, y1=3, y2=4, y3=7 ，所以答案为 [2,3,5,4,1,7]

示例 2:

输入: nums = [1,2,3,4,4,3,2,1], n = 4
输出: [1,4,2,3,3,2,4,1]

示例 3:

输入: nums = [1,1,2,2], n = 2
输出: [1,2,1,2]

提示:

• 1 <= n <= 500
• nums.length == 2n
• 1 <= nums[i] <= 10^3

题解 (Rust)

1. 题解

impl Solution {
    pub fn shuffle(nums: Vec<i32>, n: i32) -> Vec<i32> {
        let mut ret = Vec::with_capacity(2 * n as usize);

        for i in 0..(n as usize) {
            ret.push(nums[i]);
            ret.push(nums[n as usize + i]);
        }

        ret
    }
}