README_CN.md

1185. 一周中的第几天

给你一个日期，请你设计一个算法来判断它是对应一周中的哪一天。

输入为三个整数：day、month 和 year，分别表示日、月、年。

您返回的结果必须是这几个值中的一个 {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"}。

示例 1:

输入: day = 31, month = 8, year = 2019
输出: "Saturday"

示例 2:

输入: day = 18, month = 7, year = 1999
输出: "Sunday"

示例 3:

输入: day = 15, month = 8, year = 1993
输出: "Sunday"

提示:

• 给出的日期一定是在 1971 到 2100 年之间的有效日期。

题解 (Rust)

1. 题解

impl Solution {
    pub fn day_of_the_week(day: i32, month: i32, year: i32) -> String {
        let mut day = day;
        let mut months = [0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334];
        let week = ["Thursday", "Friday", "Saturday",
            "Sunday", "Monday", "Tuesday", "Wednesday"];
 
        day += (year - 1971) * 365 + (year - 1969) / 4 + months[month as usize - 1];
        if year % 4 == 0 && month > 2 {
            day += 1;
        }
        week[day as usize % 7].to_string()
    }
}