给定 pushed
和 popped
两个序列,每个序列中的 值都不重复,只有当它们可能是在最初空栈上进行的推入 push 和弹出 pop 操作序列的结果时,返回 true
;否则,返回 false
。
输入: pushed = [1,2,3,4,5], popped = [4,5,3,2,1] 输出: true 解释: 我们可以按以下顺序执行: push(1), push(2), push(3), push(4), pop() -> 4, push(5), pop() -> 5, pop() -> 3, pop() -> 2, pop() -> 1
输入: pushed = [1,2,3,4,5], popped = [4,3,5,1,2] 输出: false 解释: 1 不能在 2 之前弹出。
0 <= pushed.length == popped.length <= 1000
0 <= pushed[i], popped[i] < 1000
pushed
是popped
的排列。
# @param {Integer[]} pushed
# @param {Integer[]} popped
# @return {Boolean}
def validate_stack_sequences(pushed, popped)
stack = []
i = 0
for val in pushed
stack.push(val)
while i < popped.length and stack.last == popped[i]
stack.pop
i += 1
end
end
return stack.empty?
end
impl Solution {
pub fn validate_stack_sequences(pushed: Vec<i32>, popped: Vec<i32>) -> bool {
let mut stack = vec![];
let mut i = 0;
for val in pushed {
stack.push(val);
while i < popped.len() && *stack.last().unwrap_or(&-1) == popped[i] {
stack.pop();
i += 1;
}
}
stack.is_empty()
}
}