翻转一棵二叉树。
输入:
4 / \ 2 7 / \ / \ 1 3 6 9
输出:
4 / \ 7 2 / \ / \ 9 6 3 1
这个问题是受到 Max Howell 的 原问题 启发的 :
谷歌:我们90%的工程师使用您编写的软件(Homebrew),但是您却无法在面试时在白板上写出翻转二叉树这道题,这太糟糕了。
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def invertTree(self, root: TreeNode) -> TreeNode:
if root:
root.left, root.right = self.invertTree(root.right), self.invertTree(root.left)
return root
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def invertTree(self, root: TreeNode) -> TreeNode:
nodes = [root]
i = 0
while i < len(nodes):
if nodes[i]:
nodes.append(nodes[i].left)
nodes.append(nodes[i].right)
nodes[i].left = nodes[-1]
nodes[i].right = nodes[-2]
i += 1
return root