给定一个二叉树,返回它的前序 遍历。
输入: [1,null,2,3] 1 \ 2 / 3 输出: [1,2,3]
进阶: 递归算法很简单,你可以通过迭代算法完成吗?
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def preorderTraversal(self, root: TreeNode) -> List[int]:
if not root:
return []
return [root.val] + \
self.preorderTraversal(root.left) + \
self.preorderTraversal(root.right)
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def preorderTraversal(self, root: TreeNode) -> List[int]:
if not root:
return []
vals = []
nodes = [root]
while nodes:
node = nodes.pop()
vals.append(node.val)
if node.right:
nodes.append(node.right)
if node.left:
nodes.append(node.left)
return vals