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82. 删除排序链表中的重复元素 II

给定一个排序链表,删除所有含有重复数字的节点,只保留原始链表中 没有重复出现 的数字。

示例 1:

输入: 1->2->3->3->4->4->5
输出: 1->2->5

示例 2:

输入: 1->1->1->2->3
输出: 2->3

题解 (Ruby)

1. 题解

# Definition for singly-linked list.
# class ListNode
#     attr_accessor :val, :next
#     def initialize(val = 0, _next = nil)
#         @val = val
#         @next = _next
#     end
# end
# @param {ListNode} head
# @return {ListNode}
def delete_duplicates(head)
  dummy = ListNode.new(0, head)
  curr = dummy

  until curr.nil?
    if !curr.next.nil? && !curr.next.next.nil? && curr.next.val == curr.next.next.val
      curr.next.next = curr.next.next.next while !curr.next.next.nil? && curr.next.val == curr.next.next.val
      curr.next = curr.next.next
    else
      curr = curr.next
    end
  end

  dummy.next
end