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minimum_path_sum.cpp
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43 lines (35 loc) · 1.13 KB
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class Solution {
public:
/**
* @param grid: a list of lists of integers.
* @return: An integer, minimizes the sum of all numbers along its path
*/
int minPathSum(vector<vector<int> > &grid) {
// write your code here
// f[i][j] 到达 i j 的mini sum
// f[i][j] = min (f[i - 1][j], f[i][j - 1] + grid[i][j]
int m = grid.size();
if (m == 0) {
return 0;
}
int n = grid[0].size();
if (n == 0) {
return 0;
}
vector<vector<int>> f(m, vector<int>(n, 0));
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
int temp = 0;
if (i - 1 >= 0 && j - 1 >= 0) {
temp = min(f[i- 1][j], f[i][j - 1]);
} else if (i - 1 >= 0) {
temp = f[i - 1][j];
} else if (j - 1 >= 0) {
temp = f[i][j - 1];
}
f[i][j] = temp + grid[i][j];
}
}
return f[m - 1][n- 1];
}
};