We are given head
, the head node of a linked list containing unique integer values.
We are also given the list G
, a subset of the values in the linked list.
Return the number of connected components in G
, where two values are connected if they appear consecutively in the linked list.
Example 1:
Input: head: 0->1->2->3 G = [0, 1, 3] Output: 2 Explanation: 0 and 1 are connected, so [0, 1] and [3] are the two connected components.
Example 2:
Input: head: 0->1->2->3->4 G = [0, 3, 1, 4] Output: 2 Explanation: 0 and 1 are connected, 3 and 4 are connected, so [0, 1] and [3, 4] are the two connected components.
Note:
- If
N
is the length of the linked list given byhead
,1 <= N <= 10000
. - The value of each node in the linked list will be in the range
[0, N - 1]
. 1 <= G.length <= 10000
.G
is a subset of all values in the linked list.
Companies:
Google
Related Topics:
Linked List
// OJ: https://leetcode.com/problems/linked-list-components/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(N)
class Solution {
public:
int numComponents(ListNode* head, vector<int>& G) {
unordered_set<int> s(G.begin(), G.end());
int ans = 0;
while (true) {
while (head && s.find(head->val) == s.end()) head = head->next;
if (!head) break;
++ans;
while (head && s.find(head->val) != s.end()) head = head->next;
}
return ans;
}
};