You are given an array of strings words
and a string pref
.
Return the number of strings in words
that contain pref
as a prefix.
A prefix of a string s
is any leading contiguous substring of s
.
Example 1:
Input: words = ["pay","attention","practice","attend"], pref
= "at"
Output: 2
Explanation: The 2 strings that contain "at" as a prefix are: "attention" and "attend".
Example 2:
Input: words = ["leetcode","win","loops","success"], pref
= "code"
Output: 0
Explanation: There are no strings that contain "code" as a prefix.
Constraints:
1 <= words.length <= 100
1 <= words[i].length, pref.length <= 100
words[i]
andpref
consist of lowercase English letters.
Similar Questions:
// OJ: https://leetcode.com/problems/counting-words-with-a-given-prefix/
// Author: github.com/lzl124631x
// Time: O(NW)
// Space: O(N)
class Solution {
public:
int prefixCount(vector<string>& A, string pref) {
int ans = 0;
for (auto &s : A) {
if (s.substr(0, pref.size()) == pref) ++ans;
}
return ans;
}
};