1507

1507. Reformat Date (Easy)

Given a date string in the form Day Month Year, where:

• Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.
• Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.
• Year is in the range [1900, 2100].

Convert the date string to the format YYYY-MM-DD, where:

• YYYY denotes the 4 digit year.
• MM denotes the 2 digit month.
• DD denotes the 2 digit day.

 

Example 1:

Input: date = "20th Oct 2052"
Output: "2052-10-20"

Example 2:

Input: date = "6th Jun 1933"
Output: "1933-06-06"

Example 3:

Input: date = "26th May 1960"
Output: "1960-05-26"

 

Constraints:

• The given dates are guaranteed to be valid, so no error handling is necessary.

Related Topics:
String

Solution 1.

// OJ: https://leetcode.com/problems/reformat-date/
// Author: github.com/lzl124631x
// Time: O(1)
// Space: O(1)
class Solution {
public:
    string reformatDate(string date) {
        istringstream ss(date);
        string day, mon, year, m;
        ss >> day >> mon >> year;
        if (mon == "Jan") m = "01";
        else if (mon == "Feb") m = "02";
        else if (mon == "Mar") m = "03";
        else if (mon == "Apr") m = "04";
        else if (mon == "May") m = "05";
        else if (mon == "Jun") m = "06";
        else if (mon == "Jul") m = "07";
        else if (mon == "Aug") m = "08";
        else if (mon == "Sep") m = "09";
        else if (mon == "Oct") m = "10";
        else if (mon == "Nov") m = "11";
        else m = "12";
        string d = to_string(stoi(day));
        return year + "-" + m + "-" + (d.size() == 1? "0" + d : d);
    }
};

Solution 2.

// OJ: https://leetcode.com/problems/reformat-date/
// Author: github.com/lzl124631x
// Time: O(1)
// Space: O(1) 
class Solution {
public:
    string reformatDate(string date) {
        istringstream ss(date);
        string day, mon, year, m;
        ss >> day >> mon >> year;
        string months[12] = {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec" };
        for (int i = 0; i < 12; ++i) {
            if (months[i] == mon) {
                m = to_string(i + 1);
                if (m.size() == 1) m = "0" + m;
                break;
            }
        }
        string d = to_string(stoi(day));
        return year + "-" + m + "-" + (d.size() == 1? "0" + d : d);
    }
};