Use \range where appropriate.

(cherry picked from commit 07e995f)

Author: Eelis

source/algorithms.tex

@@ -7584,7 +7584,7 @@
 are partitioned with respect to the expressions
 \tcode{bool(invoke(comp, invoke(proj, e), value))} and
 \tcode{!bool(invoke(comp, value, invoke(proj, e)))}.
-Also, for all elements \tcode{e} of \tcode{[first, last)},
+Also, for all elements \tcode{e} of \range{first}{last},
 \tcode{bool(comp(e, value))} implies \tcode{!bool(comp(\brk{}value, e))}
 for the overloads in namespace \tcode{std}.
 
@@ -7651,7 +7651,7 @@
 are partitioned with respect to the expressions
 \tcode{bool(invoke(comp, invoke(proj, e), value))} and
 \tcode{!bool(invoke(comp, value, invoke(proj, e)))}.
-Also, for all elements \tcode{e} of \tcode{[first, last)},
+Also, for all elements \tcode{e} of \range{first}{last},
 \tcode{bool(comp(e, value))} implies \tcode{!bool(comp(\brk{}value, e))}
 for the overloads in namespace \tcode{std}.
 
@@ -10837,7 +10837,7 @@
 \pnum
 For the overloads with an \tcode{ExecutionPolicy} and a non-empty range,
 performs \tcode{*result = *first}.
-Then, for every \tcode{d} in \tcode{[1, last - first - 1]},
+Then, for every \tcode{d} in \crange{1}{last - first - 1},
 performs \tcode{*(result + d) = binary_op(*(first + d), *(first + (d - 1)))}.
 
 \pnum

source/strings.tex

@@ -151,19 +151,19 @@
 the smallest \tcode{q} in \tcode{[p,p+n)} such that
 \tcode{X::eq(*q,c)} is \tcode{true}, \tcode{nullptr} otherwise.                &   linear      \\ \rowsep
 \tcode{X::move(s,p,n)}  &   \tcode{X::char_type*}   &
-for each \tcode{i} in \tcode{[0,n)}, performs \tcode{X::assign(s[i],p[i])}.
-Copies correctly even where the ranges \tcode{[p,p+n)} and \tcode{[s,s+n)} overlap.\br \returns \tcode{s}.    &   linear  \\ \rowsep
+for each \tcode{i} in \range{0}{n}, performs \tcode{X::assign(s[i],p[i])}.
+Copies correctly even where the ranges \range{p}{p+n} and \range{s}{s+n} overlap.\br \returns \tcode{s}.    &   linear  \\ \rowsep
 \tcode{X::copy(s,p,n)}  &   \tcode{X::char_type*}   &
  \expects
 The ranges \range{p}{p+n} and \range{s}{s+n} do not overlap.\par
  \returns
 \tcode{s}.\br
 for each \tcode{i} in
-\tcode{[0,n)}, performs \tcode{X::assign(s[i],p[i])}.               &   linear      \\ \rowsep
+\range{0}{n}, performs \tcode{X::assign(s[i],p[i])}.               &   linear      \\ \rowsep
 \tcode{X::assign(r,d)}  &   (not used)          &
 assigns \tcode{r=d}.                            &   constant        \\ \rowsep
 \tcode{X::assign\-(s,n,c)}  &   \tcode{X::char_type*}   &
-for each \tcode{i} in \tcode{[0,n)}, performs
+for each \tcode{i} in \range{0}{n}, performs
 \tcode{X::assign(s[i],c)}.\br
  \returns
 \tcode{s}.                       &   linear      \\ \rowsep