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sumcloset3.java
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// source: https://leetcode.com/problems/3sum-closest/
// difficulty: Medium
// Author: Chen
// Date: Jul-18-2024
/****************************************************************************************************************************
* Given an integer array nums of length n and an integer target, find three integers in nums such that the sum is closest to target.
* Return the sum of the three integers.
* You may assume that each input would have exactly one solution.
*
* Example 1:
* Input: nums = [-1,2,1,-4], target = 1
* Output: 2
* Explanation: The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
* Example 2:
* Input: nums = [0,0,0], target = 1
* Output: 0
* Explanation: The sum that is closest to the target is 0. (0 + 0 + 0 = 0).
* Constraints:
* 3 <= nums.length <= 500
* -1000 <= nums[i] <= 1000
* -104 <= target <= 104
**************************************************************************************************************************/
// Solution: sort the array, then use two pointers to find the closest sum
// Time complexity: O(n^2), Space complexity: O(1)
class Solution {
Character.getNumericValue
public int threeSumClosest(int[] nums, int target) {
int near = Integer.MAX_VALUE;
int diff = Integer.MAX_VALUE;
Arrays.sort(nums);
for(int i=0 ; i<nums.length - 2; i++){
int j = i +1;
int k = nums.length -1;
while( j < k){
int sum = nums[i] + nums[j] + nums[k];
if(sum == target){
return sum;
}else if( sum < target ){
if( target - sum < diff){
diff = target - sum;
near = sum;
}
j++;
}else {
if(sum - target < diff){
diff = sum - target;
near = sum;
}
k--;
}
}
}
return near;
}
}