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Copy pathstringmethod.py
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115 lines (62 loc) · 1.4 KB
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s="my name is ankit."
# z=s.capitalize()
# print(s)
# print(z)
# x=s.casefold()
# print(s)
# print(x)
# name="ankit"
# n=name.capitalize()
# print(n.center(5,'-'))
# print(n.count('i'))
# s="k\to\tl\tk\tt\ta"
# print(s.expandtabs(4))
# s="ankit"
# print(s.lower())
# print(s.upper())
# s="my name is ankit"
# print(s.split())
# s="my-name-is-ankit"
# print(s.split())
# s="my name is ankit"
# print(s.title())
# print(s.swapcase())
# s=" ankit "
# print(s.strip())
# print(s.lstrip())
# print(s.rstrip())
# s="my name is ankit"
# print(''.join(s))
# s='50'
# print(s.zfill(10))
# print(s.isdigit())
# s="kolaktai"
# print(s.find('i'))
# s="ian ainni kii"
# print(s.rfind('k'))
# print(s.index('a'))
# print(s.rindex('n'))
# s="my name is ankit"
# print(s.replace('name','naam'))
# s="my name is {}, i am {} year lod."
# print(s.format("ankit",18))
#lex_auth_012693816331657216161
def encode(message):
text = ""
count = 0
c = message[0]
for i in range(0,len(message)):
if c == message[i]:
count+=1
else:
text += str(count)
text += message[i-1]
c=message[i]
count=1
text += str(count)
text += c
return text
#Remove pass and write your logic here
#Provide different values for message and test your program
encoded_message=encode("ABBBBCCCCCCCCAB")
print(encoded_message)