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solution.java
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solution.java
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import java.util.*;
import java.io.*;
class Node {
Node left;
Node right;
int data;
Node(int data) {
this.data = data;
left = null;
right = null;
}
}
class solution {
//new class to store level of each node along with the node
static class QueueNode{
Node node;
int level;
public QueueNode(Node node, int level){
this.node = node;
this.level = level;
}
}
public static void topView(Node root) {
//took a queue - similar to BFS approach
Queue<QueueNode> queue = new LinkedList<QueueNode>();
//Taking a TreeMap<first, second>
//first - stores the level of the node
//second - stores the node.data
TreeMap<Integer, Integer> map = new TreeMap<Integer, Integer>();
//why TreeMap because the nodes to be sorted from leftmost to rightmost
//start (since root, level = 0)
queue.add(new QueueNode(root, 0));
while(!queue.isEmpty()){
//remove element from queue
QueueNode r = queue.poll();
//if the level of this node has never been reached before -> visible in top view
if(!map.containsKey(r.level)){
map.put(r.level, r.node.data);
}
//add node's descendants
//all left child node levels = node.level - 1
//all right child node levels = node.level + 1
if(r.node.left != null){
queue.add(new QueueNode(r.node.left, r.level - 1));
}
if(r.node.right != null){
queue.add(new QueueNode(r.node.right, r.level + 1));
}
}
//since already sorted (cuz TreeMap), print from left to right
for (Integer value : map.values()) {
System.out.print(value + " ");
}
}
public static Node insert(Node root, int data) {
if(root == null) {
return new Node(data);
} else {
Node cur;
if(data <= root.data) {
cur = insert(root.left, data);
root.left = cur;
} else {
cur = insert(root.right, data);
root.right = cur;
}
return root;
}
}
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int t = scan.nextInt();
Node root = null;
while(t-- > 0) {
int data = scan.nextInt();
root = insert(root, data);
}
scan.close();
topView(root);
}
}