[1] Open URL, Web or Safari link

[SwiftfulThinking]

Task

Add the ability to show a URL

Details:

1. Create a new function with similar syntax to "showSheet", called "showUrl" that accepts a URL as a parameter and has 3 options.

2. Safari support. Should open URL in Safari application.

router.showUrl(.safari) {
     URL("https://www.google.com")
}

3. In App Web Browser support. Should open URL in an in-app browser (probably need to add a SFSafariViewControllerRepresentable). Need to be able to dismiss this.

router.showUrl(.inAppBrowser) {
     URL("https://www.google.com")
}

4. URL Schema Support. Should open the URL directly via UIApplication.shared.open(url) or similar.

router.showUrl(.urlSchema) {
     URL("https://www.google.com")
}

5. Add back-ward support to iOS 13 where possible