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105. Construct Binary Tree from Preorder and Inorder Traversal.cpp
add the solution of leetcode question number 105
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/**
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* Definition for a binary tree node.
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* struct TreeNode {
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* int val;
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* TreeNode *left;
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* TreeNode *right;
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* TreeNode() : val(0), left(nullptr), right(nullptr) {}
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* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
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* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
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* };
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*/
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class Solution {
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public:
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unordered_map<int,int> mp;
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TreeNode* build(int il,int ir,int pl,int pr,vector<int> &preorder,vector<int> &inorder){
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if(il>ir) return NULL;
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TreeNode* cur_node = new TreeNode(preorder[pl]);
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if(il==ir) return cur_node;
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int inorder_ind = mp[preorder[pl]];
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int m = pl+inorder_ind-il;
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cur_node->left = build(il,inorder_ind-1,pl+1,m,preorder,inorder);
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cur_node->right = build(inorder_ind+1,ir,m+1,pr,preorder,inorder);
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return cur_node;
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}
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TreeNode* buildTree(vector<int>& preorder, vector<int>& inorder) {
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int n = inorder.size();
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for(int i=0;i<n;i++){
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mp[inorder[i]] = i;
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}
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return build(0,n-1,0,n-1,preorder,inorder);
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}
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};

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