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| 1 | +/** |
| 2 | + * Definition for a binary tree node. |
| 3 | + * struct TreeNode { |
| 4 | + * int val; |
| 5 | + * TreeNode *left; |
| 6 | + * TreeNode *right; |
| 7 | + * TreeNode() : val(0), left(nullptr), right(nullptr) {} |
| 8 | + * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} |
| 9 | + * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} |
| 10 | + * }; |
| 11 | + */ |
| 12 | +class Solution { |
| 13 | +public: |
| 14 | + unordered_map<int,int> mp; |
| 15 | + TreeNode* build(int il,int ir,int pl,int pr,vector<int> &preorder,vector<int> &inorder){ |
| 16 | + if(il>ir) return NULL; |
| 17 | + TreeNode* cur_node = new TreeNode(preorder[pl]); |
| 18 | + if(il==ir) return cur_node; |
| 19 | + int inorder_ind = mp[preorder[pl]]; |
| 20 | + int m = pl+inorder_ind-il; |
| 21 | + cur_node->left = build(il,inorder_ind-1,pl+1,m,preorder,inorder); |
| 22 | + cur_node->right = build(inorder_ind+1,ir,m+1,pr,preorder,inorder); |
| 23 | + return cur_node; |
| 24 | + } |
| 25 | + TreeNode* buildTree(vector<int>& preorder, vector<int>& inorder) { |
| 26 | + int n = inorder.size(); |
| 27 | + for(int i=0;i<n;i++){ |
| 28 | + mp[inorder[i]] = i; |
| 29 | + } |
| 30 | + return build(0,n-1,0,n-1,preorder,inorder); |
| 31 | + } |
| 32 | +}; |
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