CountOfTournament.c

#include <stdio.h>

/* You are given an integer n, the number of teams in a tournament that has strange rules:
If the current number of teams is even, each team gets paired with another team. A total of n / 2 matches are played, and n / 2 teams advance to the next round.
If the current number of teams is odd, one team randomly advances in the tournament, and the rest gets paired. A total of (n - 1) / 2 matches are played, and (n - 1) / 2 + 1 teams advance to the next round.
Return the number of matches played in the tournament until a winner is decided. */

int main()
{
    int n;
    scanf("Enter number of players %d\n", n);

    int match = 0;

    while (n > 1)
    {
        if (n % 2 != 0)
        {
            match += (n - 1) / 2;
            n = ((n - 1) / 2) + 1;
        }
        else
        {
            match += (n/2) ;
            n = n/2;
        }
    }
    
    printf("Count of matches are %d\n", match);
    return 0;
}