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Copy pathK Radius Subarray Averages.cpp
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K Radius Subarray Averages.cpp
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/*
Solution by Rahul Surana
***********************************************************
You are given a 0-indexed array nums of n integers, and an integer k.
The k-radius average for a subarray of nums centered at some index i with the radius k is the average of all elements in nums
between the indices i - k and i + k (inclusive).
If there are less than k elements before or after the index i, then the k-radius average is -1.
Build and return an array avgs of length n where avgs[i] is the k-radius average for the subarray centered at index i.
The average of x elements is the sum of the x elements divided by x, using integer division. The integer division truncates toward zero,
which means losing its fractional part.
For example, the average of four elements 2, 3, 1, and 5 is (2 + 3 + 1 + 5) / 4 = 11 / 4 = 2.75, which truncates to 2.
***********************************************************
*/
class Solution {
public:
vector<int> getAverages(vector<int>& nums, int k) {
long s = 0;
int n = nums.size();
for(int i = 0; i < k && i < n; i++) s+= nums[i];
vector<int> ans(n,-1);
for(int i = 0; i < n; i++){
if(i+k < n) {
s+= nums[i+k];
if(i >= k){
ans[i] = (s/((2*k)+1));
s-=nums[i-k];
}
}
}
return ans;
}
};