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code.cpp
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/* **************************************************************************
* Copyright 2024 The OpenGenus.org Authors. All Rights Reserved.
*
* Code for the book "DAILY 43: Algorithmic Problems for Coding Interviews: Easy level, C++ edition"
*
* Licensed under the GNU General Public License, Version 3.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.gnu.org/licenses/gpl-3.0.html
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*
* For details about the book, please visit: https://www.amazon.com/dp/B0CZJNBLQS
* *************************************************************************/
#include <iostream>
struct TreeNode {
int val;
TreeNode* left;
TreeNode* right;
TreeNode(int val) : val(val), left(nullptr), right(nullptr) {}
};
TreeNode* invertTree(TreeNode* root) {
if (root) {
TreeNode* temp = root->left;
root->left = root->right;
root->right = temp;
invertTree(root->left);
invertTree(root->right);
}
return root;
}
// Utility function to print the tree in inorder traversal
void printInorder(TreeNode* root) {
if (root) {
printInorder(root->left);
std::cout << root->val << " ";
printInorder(root->right);
}
}
int main() {
// Create a binary tree
TreeNode* root = new TreeNode(4);
root->left = new TreeNode(2);
root->right = new TreeNode(7);
root->left->left = new TreeNode(1);
root->left->right = new TreeNode(3);
root->right->left = new TreeNode(6);
root->right->right = new TreeNode(9);
std::cout << "Original Tree (inorder): ";
printInorder(root);
std::cout << std::endl;
// Invert the tree
TreeNode* invertedTree = invertTree(root);
std::cout << "Inverted Tree (inorder): ";
printInorder(invertedTree);
std::cout << std::endl;
return 0;
}