readnewick and empty taxon names

[colbec]

Forgive my unfamiliarity with the detail of the Newick format - when I attempt to read in the string
tree = "((A,B),(,));"
the readnewick() parser chokes on the "(,)" and cannot proceed. I have seen this frequently in example strings.
Does the parser not handle this at this time?

[cecileane]

No, leaves need to have a label. In your example, there are 2 leaves without labels, as part of this near the end: (,).
The following should work:

julia> tree = "((A,B),(fakelabel1,fakelabel2));" ;

julia> readnewick(tree)
HybridNetwork, Rooted Network
6 edges
7 nodes: 4 tips, 0 hybrid nodes, 3 internal tree nodes.
tip labels: A, B, fakelabel1, fakelabel2
((A,B),(fakelabel1,fakelabel2));

[colbec]

Thanks, this was helpful. For others in the same situation the following process worked for me to produce a raw string that the parser was happy with. Whether the final result is the tree that the original author intended is another matter. It is a very pedestrian and inefficient process but allows for examination of intermediate steps in case further problems arise.

while occursin("(,)",tree)
    x = randstring('A':'Z',6)
    y = randstring('A':'Z',7)
    tree = replace(tree,"(,)"=>"($x,$y)",count=1)
end
while occursin(",)",tree)
    z = randstring('A':'Z',6)
    tree = replace(tree,",)"=>",$z)",count=1)
end
while occursin("(,",tree)
    z = randstring('A':'Z',6)
    tree = replace(tree,"(,"=>"($z,",count=1)
end
while occursin(",,",tree)
    z = randstring('A':'Z',6)
    tree = replace(tree,",,"=>",$z,",count=1)
end
while occursin("()",tree)
    z = randstring('A':'Z',6)
    tree = replace(tree,"()"=>"($z)",count=1)
end