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Description
I'm attempting to use a django filter while continuing using the encrypted id.
I can do this -
http://localhost:8000/api/v1/widget/?id=3
but I can't do this -
http://localhost:8000/api/v1/widget/?id=zspnn6wva2rd47z44jo65bi6iy
doing so generates the following error:
invalid literal for int() with base 10: 'zspnn6wva2rd47z44jo65bi6iy'
which makes sense because it's expecting an integer.
I'm using django-filter like so:
class WidgetFilter(django_filters.FilterSet):
id = django_filters.CharFilter(name='id', lookup_type='exact')
name = django_filters.CharFilter(name='username', lookup_type='exact')
list = django_filters.CharFilter(name='list__name', lookup_type='exact')
class Meta:
model = Widget
fields = ['id', 'username', 'list__name']
When I query the actual ID it does return the encrypted value and I can query like this:
http://localhost:8000/api/v1/widget/zspnn6wva2rd47z44jo65bi6iy/
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