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longest_common_substring.c
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longest_common_substring.c
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// C program to find to the longest common substring along with its length
#include <stdio.h>
// Helper function to find the maximum of two elements
int max(int a, int b)
{
if (a > b)
return a;
else
return b;
}
// Length of Longest Common substring
void lcs(char s1[], int n, char s2[], int m)
{
/*
Builds a 2D table in a bottom Up manner, storing info
regarding the length of longest common substring till that index.
*/
int dp[n + 1][m + 1], ans = 0;
for (int i = 0; i <= n; i++)
{
for (int j = 0; j <= m; j++)
{
// If one of the string size is zero, then the length of LCS is also zero
if (i == 0 || j == 0)
dp[i][j] = 0;
/* If the elements of both the strings match, then the value of LCS increments by one.
Also Check if the value of lcs has reached the max till now.
*/
else if (s1[i - 1] == s2[j - 1])
{
dp[i][j] = dp[i - 1][j - 1] + 1;
ans = max(ans, dp[i][j]);
}
else
dp[i][j] = 0;
}
}
int index = ans;
char lcs[index+1];
lcs[index] = '\0';
int i = n, j = m;
while (i > 0 && j > 0)
{
if (s1[i-1] == s2[j-1])
{
lcs[index-1] = s1[i-1];
i--;
j--;
index--;
}
else if (dp[i-1][j] > dp[i][j-1])
{
i--;
}
else
{
j--;
}
}
printf("The length of the longest common substring is: %d and the substring is %s.", ans, lcs);
}
int main()
{
int n, m;
printf("\nEnter the length of the first string? ");
scanf("%d", &n);
char s1[n];
printf("Enter the first string: ");
scanf(" %s", s1);
printf("\nEnter the length of the second string? ");
scanf("%d", &m);
char s2[m];
printf("Enter the second string: ");
scanf(" %s", s2);
lcs(s1, n, s2, m);
return 0;
}
/*
Time Complexity: O(m*n), where m, n is the size of the input strings
Space Complexity: O(m*n)
SAMPLE INPUT AND OUTPUT
Enter the length of the first string? 8
Enter the first string: cucumber
Enter the length of the second string? 6
Enter the second string: cuckoo
The length of the longest common substring is: 3 and the substring is cuc.
*/