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Author: DeependraParmar

24_pointerswithFunctions.cpp

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+#include <iostream>
+using namespace std;
+void printValue(int* p){
+    cout<<"Address stored by the pointer is: "<<p<<endl;
+    cout<<"Value at the address stored by the pointer is: "<<*p<<endl;
+}
+void update(int* p){
+    p++;
+}
+int main(){
+    // Pointers can be passed in the functions as well.
+    int n = 3;
+    int* ptr = &n;
+
+    printValue(ptr);//this print function is going to print the address and value of the pointer 
+    cout<<endl;
+    // Now what we are going to do is going to create a function update() which is going to update the value at address stored by the pointer and lets see it will going to do it or not 
+    cout<<"Before change,address stored by pointer is: "<< ptr<<endl;
+    update(ptr);
+    cout<<"After change,address stored by the pointer is: "<< ptr <<endl;// evne after updation , address is not gonna change because here the pointer is pass by value which means a copy of the pointer is being created in the update function and the address is changed within the scope of it and is not getting reflected in the main(); Then whats the solution: either print the address inside the update function or use reference variables.
+
+
+    return 0;
+}