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| 1 | +/** |
| 2 | + * [Problem]: [213] House Robber II |
| 3 | + * (https://leetcode.com/problems/house-robber-ii/description/) |
| 4 | + */ |
| 5 | +function rob(nums: number[]): number { |
| 6 | + //시간복잡도 O(n) |
| 7 | + //공간복잡도 O(n) |
| 8 | + function memoizationFunc(nums: number[]): number { |
| 9 | + const memo = new Map<string, number>(); |
| 10 | + const length = nums.length; |
| 11 | + |
| 12 | + function dfs(idx: number, first = false) { |
| 13 | + const key = `${idx}_${first}`; |
| 14 | + if (memo.has(key)) return memo.get(key)!; |
| 15 | + |
| 16 | + if (idx === length - 1) return first ? 0 : nums[idx]; |
| 17 | + if (idx >= length) return 0; |
| 18 | + if (idx === 0) { |
| 19 | + const result = Math.max(nums[0] + dfs(2, true), dfs(1, false)); |
| 20 | + memo.set(key, result); |
| 21 | + return result; |
| 22 | + } |
| 23 | + |
| 24 | + const result = Math.max(nums[idx] + dfs(idx + 2, first), dfs(idx + 1, first)); |
| 25 | + memo.set(key, result); |
| 26 | + return result; |
| 27 | + } |
| 28 | + |
| 29 | + return dfs(0); |
| 30 | + } |
| 31 | + |
| 32 | + //시간복잡도 O(n) |
| 33 | + //공간복잡도 O(1) |
| 34 | + function dpFunc(nums: number[]): number { |
| 35 | + if (nums.length === 1) return nums[0]; |
| 36 | + |
| 37 | + function dp(start: number, end: number) { |
| 38 | + let prev = 0; |
| 39 | + let cur = 0; |
| 40 | + |
| 41 | + for (let i = start; i < end; i++) { |
| 42 | + [prev, cur] = [cur, Math.max(prev + nums[i], cur)]; |
| 43 | + } |
| 44 | + |
| 45 | + return cur; |
| 46 | + } |
| 47 | + |
| 48 | + return Math.max(dp(0, nums.length - 1), dp(1, nums.length)); |
| 49 | + } |
| 50 | +} |
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