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86 changes: 69 additions & 17 deletions 02_activities/assignments/assignment1.sql
Original file line number Diff line number Diff line change
@@ -1,73 +1,111 @@

--Module: SQL
--Name: Chun-Yuan Chen
--Assignment: 1
--Sections: 2 & 3


/* ASSIGNMENT 1 */
/* SECTION 2 */


--SELECT
/* 1. Write a query that returns everything in the customer table. */


SELECT * FROM customer;

/* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table,
sorted by customer_last_name, then customer_first_ name. */

SELECT * FROM customer
ORDER BY customer_last_name, customer_first_name
LIMIT 10;


--WHERE
/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
-- option 1

SELECT * FROM customer_purchases
WHERE product_id = 4 OR product_id = 9; /* Note: I found no records with product_id = 9 in the dataset. */

-- option 2


SELECT * FROM customer_purchases
WHERE product_id IN (4,9);

/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty),
filtered by vendor IDs between 8 and 10 (inclusive) using either:
1. two conditions using AND
2. one condition using BETWEEN
*/
-- option 1

SELECT *, quantity * cost_to_customer_per_qty AS price
FROM customer_purchases
WHERE vendor_id >= 8 AND vendor_id <= 10; /* Note: I found no records with vendor_id = 9 or 10 in the dataset. */

-- option 2

SELECT *, quantity * cost_to_customer_per_qty AS price
FROM customer_purchases
WHERE vendor_id BETWEEN 8 AND 10; /* Note: Just curious myself, unsure if BETWEEN can be set as inclusive or exclusive like other languages. */

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BETWEEN is always inclusive (both ends)



--CASE
/* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz.
Using the product table, write a query that outputs the product_id and product_name
columns and add a column called prod_qty_type_condensed that displays the word “unit”
if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */


SELECT product_id, product_name,
CASE
WHEN product_qty_type = 'unit' THEN 'unit'
WHEN product_qty_type IS NULL THEN NULL /* Note: I added this command in order to account for NULL in the product_qty_type column. */
ELSE 'bulk'
END AS prod_qty_type_condensed
FROM product;

/* 2. We want to flag all of the different types of pepper products that are sold at the market.
add a column to the previous query called pepper_flag that outputs a 1 if the product_name
contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */

SELECT product_id, product_name,
CASE
WHEN product_qty_type = 'unit' THEN 'unit'
WHEN product_qty_type IS NULL THEN NULL
ELSE 'bulk'
END AS prod_qty_type_condensed,
CASE
WHEN product_name LIKE '%pepper%' THEN 1
ELSE 0
END AS pepper_flag
FROM product;


--JOIN
/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the
vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */

SELECT v.*, vba.booth_number, vba.market_date
FROM vendor v
INNER JOIN vendor_booth_assignments vba ON v.vendor_id = vba.vendor_id
ORDER BY v.vendor_name ASC, vba.market_date ASC; /* Note: I added ASC just in case.*/



/* SECTION 3 */


-- AGGREGATE
/* 1. Write a query that determines how many times each vendor has rented a booth
at the farmer’s market by counting the vendor booth assignments per vendor_id. */


SELECT vendor_id, COUNT(*) AS booth_rental_count /* Note: I determined using an asterisk after confirming no redundant or empty rows.*/
FROM vendor_booth_assignments
GROUP BY vendor_id;

/* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper
sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list
of customers for them to give stickers to, sorted by last name, then first name.

HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */

SELECT c.customer_id, c.customer_first_name, c.customer_last_name, SUM(cp.quantity * cp.cost_to_customer_per_qty) AS total_spent
FROM customer c
INNER JOIN customer_purchases cp ON c.customer_id = cp.customer_id
GROUP BY c.customer_id
HAVING total_spent > 2000
ORDER BY c.customer_last_name ASC, c.customer_first_name ASC;


--Temp Table
Expand All @@ -81,20 +119,34 @@ When inserting the new vendor, you need to appropriately align the columns to be
-> To insert the new row use VALUES, specifying the value you want for each column:
VALUES(col1,col2,col3,col4,col5)
*/
DROP TABLE IF EXISTS temp.new_vendor;

CREATE TABLE temp.new_vendor AS
SELECT * FROM vendor;

INSERT INTO new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
VALUES (10, 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal');

SELECT * FROM new_vendor;


-- Date
/*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.

HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month
and year are! */


SELECT customer_id, strftime('%m', market_date) AS month, strftime('%Y', market_date) AS year
FROM customer_purchases;

/* 2. Using the previous query as a base, determine how much money each customer spent in April 2022.
Remember that money spent is quantity*cost_to_customer_per_qty.

HINTS: you will need to AGGREGATE, GROUP BY, and filter...
but remember, STRFTIME returns a STRING for your WHERE statement!! */
SELECT customer_id, strftime('%m', market_date) AS month, strftime('%Y', market_date) AS year, SUM(quantity * cost_to_customer_per_qty) AS total_spent /* Note: The last one for the aggregate purpose. */
FROM customer_purchases
WHERE month = '04' AND year = '2022' /* Note: Here for the filter purpose. */
GROUP BY customer_id; /* Note: Here for the group by purpose. */


/* Completed! */