feat: solve No.1560

Author: BaffinLee

Diff for: 1501-1600/1560. Most Visited Sector in a Circular Track.md

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+# 1560. Most Visited Sector in  a Circular Track
+
+- Difficulty: Easy.
+- Related Topics: Array, Simulation.
+- Similar Questions: .
+
+## Problem
+
+Given an integer `n` and an integer array `rounds`. We have a circular track which consists of `n` sectors labeled from `1` to `n`. A marathon will be held on this track, the marathon consists of `m` rounds. The `ith` round starts at sector `rounds[i - 1]` and ends at sector `rounds[i]`. For example, round 1 starts at sector `rounds[0]` and ends at sector `rounds[1]`
+
+Return **an array of the most visited sectors** sorted in **ascending** order.
+
+Notice that you circulate the track in ascending order of sector numbers in the counter-clockwise direction (See the first example).
+
+ 
+Example 1:
+
+![](https://assets.leetcode.com/uploads/2020/08/14/tmp.jpg)
+
+```
+Input: n = 4, rounds = [1,3,1,2]
+Output: [1,2]
+Explanation: The marathon starts at sector 1. The order of the visited sectors is as follows:
+1 --> 2 --> 3 (end of round 1) --> 4 --> 1 (end of round 2) --> 2 (end of round 3 and the marathon)
+We can see that both sectors 1 and 2 are visited twice and they are the most visited sectors. Sectors 3 and 4 are visited only once.
+```
+
+Example 2:
+
+```
+Input: n = 2, rounds = [2,1,2,1,2,1,2,1,2]
+Output: [2]
+```
+
+Example 3:
+
+```
+Input: n = 7, rounds = [1,3,5,7]
+Output: [1,2,3,4,5,6,7]
+```
+
+ 
+**Constraints:**
+
+
+	
+- `2 <= n <= 100`
+	
+- `1 <= m <= 100`
+	
+- `rounds.length == m + 1`
+	
+- `1 <= rounds[i] <= n`
+	
+- `rounds[i] != rounds[i + 1]` for `0 <= i < m`
+
+
+
+## Solution
+
+```javascript
+/**
+ * @param {number} n
+ * @param {number[]} rounds
+ * @return {number[]}
+ */
+var mostVisited = function(n, rounds) {
+    var start = rounds[0];
+    var end = rounds[rounds.length - 1];
+    if (end >= start) {
+        return Array(end - start + 1).fill(0).reduce((arr, num, i) => {
+            arr.push(start + i);
+            return arr;
+        }, []);
+    } else {
+        var arr1 = Array(n - start + 1).fill(0).reduce((arr, num, i) => {
+            arr.push(start + i);
+            return arr;
+        }, []);
+        var arr2 = Array(end).fill(0).reduce((arr, num, i) => {
+            arr.push(i + 1);
+            return arr;
+        }, []);
+        return arr2.concat(arr1);
+    }
+};
+```
+
+**Explain:**
+
+if start <= end, return range[start, end]
+
+else return range[0, end] + range[start, n]
+
+**Complexity:**
+
+* Time complexity : O(n).
+* Space complexity : O(n).