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| 1 | +class Solution { |
| 2 | +public: |
| 3 | + int largestRectangleArea(vector<int>& A) { |
| 4 | + int n=A.size(); |
| 5 | + stack<int>s; |
| 6 | + vector<int>nsr; |
| 7 | + for(int i=n-1;i>=0;i--) |
| 8 | + { |
| 9 | + if(s.empty()) |
| 10 | + { |
| 11 | + nsr.push_back(n); |
| 12 | + } |
| 13 | + else if(A[s.top()]<A[i]) |
| 14 | + { |
| 15 | + nsr.push_back(s.top()); |
| 16 | + } |
| 17 | + else if(A[s.top()]>=A[i]) |
| 18 | + { |
| 19 | + while(!s.empty()&&A[s.top()]>=A[i]) |
| 20 | + { |
| 21 | + s.pop(); |
| 22 | + } |
| 23 | + if(s.empty()) |
| 24 | + { |
| 25 | + nsr.push_back(n); |
| 26 | + } |
| 27 | + else |
| 28 | + nsr.push_back(s.top()); |
| 29 | + } |
| 30 | + s.push(i); |
| 31 | + } |
| 32 | + reverse(nsr.begin(),nsr.end()); |
| 33 | + stack<int>ss; |
| 34 | + vector<int>nsl; |
| 35 | + for(int i=0;i<n;i++) |
| 36 | + { |
| 37 | + if(ss.empty()) |
| 38 | + { |
| 39 | + nsl.push_back(-1); |
| 40 | + } |
| 41 | + else if(A[ss.top()]<A[i]) |
| 42 | + { |
| 43 | + nsl.push_back(ss.top()); |
| 44 | + } |
| 45 | + else if(A[ss.top()]>=A[i]) |
| 46 | + { |
| 47 | + while(!ss.empty()&&A[ss.top()]>=A[i]) |
| 48 | + ss.pop(); |
| 49 | + if(ss.empty()) |
| 50 | + { |
| 51 | + nsl.push_back(-1); |
| 52 | + } |
| 53 | + else |
| 54 | + nsl.push_back(ss.top()); |
| 55 | + } |
| 56 | + ss.push(i); |
| 57 | + } |
| 58 | + int ans=0; |
| 59 | + for(int i=0;i<n;i++) |
| 60 | + { |
| 61 | + ans=max(ans,(nsr[i]-nsl[i]-1)*A[i]); |
| 62 | + } |
| 63 | + return ans; n=A.size(); |
| 64 | + stack<int>s; |
| 65 | + vector<int>nsr; |
| 66 | + for(int i=n-1;i>=0;i--) |
| 67 | + { |
| 68 | + if(s.empty()) |
| 69 | + { |
| 70 | + nsr.push_back(n); |
| 71 | + } |
| 72 | + else if(A[s.top()]<A[i]) |
| 73 | + { |
| 74 | + nsr.push_back(s.top()); |
| 75 | + } |
| 76 | + else if(A[s.top()]>=A[i]) |
| 77 | + { |
| 78 | + while(!s.empty()&&A[s.top()]>=A[i]) |
| 79 | + { |
| 80 | + s.pop(); |
| 81 | + } |
| 82 | + if(s.empty()) |
| 83 | + { |
| 84 | + nsr.push_back(n); |
| 85 | + } |
| 86 | + else |
| 87 | + nsr.push_back(s.top()); |
| 88 | + } |
| 89 | + s.push(i); |
| 90 | + } |
| 91 | + reverse(nsr.begin(),nsr.end()); |
| 92 | + stack<int>ss; |
| 93 | + vector<int>nsl; |
| 94 | + for(int i=0;i<n;i++) |
| 95 | + { |
| 96 | + if(ss.empty()) |
| 97 | + { |
| 98 | + nsl.push_back(-1); |
| 99 | + } |
| 100 | + else if(A[ss.top()]<A[i]) |
| 101 | + { |
| 102 | + nsl.push_back(ss.top()); |
| 103 | + } |
| 104 | + else if(A[ss.top()]>=A[i]) |
| 105 | + { |
| 106 | + while(!ss.empty()&&A[ss.top()]>=A[i]) |
| 107 | + ss.pop(); |
| 108 | + if(ss.empty()) |
| 109 | + { |
| 110 | + nsl.push_back(-1); |
| 111 | + } |
| 112 | + else |
| 113 | + nsl.push_back(ss.top()); |
| 114 | + } |
| 115 | + ss.push(i); |
| 116 | + } |
| 117 | + int ans=0; |
| 118 | + for(int i=0;i<n;i++) |
| 119 | + { |
| 120 | + ans=max(ans,(nsr[i]-nsl[i]-1)*A[i]); |
| 121 | + } |
| 122 | + return ans; |
| 123 | + } |
| 124 | +}; |
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